All categories

3 years ago

Magnetic fields are produced either by electric currents or time-varying electric fields.

Physics

1 answer:

Fynjy0 [20]3 years ago

6 0

Answer:

option (a)

Explanation:

The magnetic field is produced by the electric current, and the direction of magnetic field is given by the Maxwells' right hand rule.

The magnetic field is also be produced by the time varying magnetic fields.

You might be interested in

At the instant a traffic light turns green, a car starts with a constant acceleration of 1.3 m/s2. At the same instant a truck,

Bas_tet [7]

Answer:

(a) Distance traveled = 75.3846 m

(b) Velocity of car at that instant will be 14 m/sec

Explanation:

We have given acceleration of the car $a=1.3m/sec^2$

Initial velocity of the cart u = 0 m/sec

(a) According to second equation of motion we know that $s=ut+\frac{1}{2}at^2$

So distance traveled by car $s_c=0\times t+\frac{1}{2}\times 1.3t^2=0.65t^2$

As the truck is moving with constant speed

So distance traveled by truck $s_t=ut=7t$

As the truck overtakes the car

So $s_c=s_t$

$0.65t^2=7t$

$t=10.769sec$

So distance traveled $s_c=s_t=7\times 10.769=75.3846m$

(b) From second equation of motion we know that v = u+at

So v = 0+1.3×10.769 = 14 m /sec

7 0

3 years ago

Got an F in Physical Science. HELP ME PLZZZ

Dmitriy789 [7]

i know can you plzz help me with this question im sorry i didt answer your question i just need hel.

7 0

3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this

Ne4ueva [31]

Answer:

In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.

Explanation:

Horizontal reach formula for projectiles tells us

$d=\frac{v_i^2\sin(2\theta)}{g},$

where $v_i$ is the initial velocity and $\theta$ the angle above the horizontal.

Since for both shots the reach must be the same, we have

$\frac{v_i^2\sin(2\theta_1)}{g}=\frac{v_i^2\sin(2\theta_2)}{g}\\\sin(2\theta_1)=\sin(2\theta_2)\\\theta_2=\frac{1}{2}\arcsin(\sin(2\theta_1))=\frac{1}{2}\arcsin(\sin(2\times 72\deg))=\mathbf{18\deg}$ .

8 0

4 years ago

Suppose you want to use this human engine to lift a 2.35 kg box from the floor to a tabletop 1.30 m above the floor. How much mu

morpeh [17]

Answer:

The increase in the gravitational potential energy is 29.93 joules.

Explanation:

Given that,

Mass of the box, m = 2.35 kg

It is lifted from the floor to a tabletop 1.30 m above the floor, h = 1.3 m

We need to find the increase the gravitational potential energy. Initial it will placed at ground i.e. its initial gravitational potential is equal to 0. The increase in the gravitational potential energy is given by :

$U=mgh$

$U=2.35\ kg\times 9.8\ m/s^2\times 1.3\ m$

U = 29.93 Joules

So, the increase in the gravitational potential energy is 29.93 joules. Hence, this is the required solution.

6 0

4 years ago

Convert time from 12-hour to 24-hour clock.

Kamila [148]

22:54 is the answer you are looking for

6 0

3 years ago