#6). The tangent of an angle in a right triangle is
(opposite side) / (adjacent side) .
The side opposite the marked angle is 4cm.
The side adjacent to the marked angle is 12cm.
The tangent of the marked angle is (4cm / 12cm) = 1/3 .
The marked angle is the angle whose tangent is 1/3 .
You can find that online, or with your calculator, slide rule, Curta, or book.
#7). The cosine of an angle in a right triangle is
(adjacent side) / (hypotenuse) .
The side adjacent to the marked angle is 15m.
The hypotenuse is 19m.
The cosine of the marked angle is (15m / 19m) = about 0.78947...
The marked angle is the angle whose cosine is 0.78947... .
You can find that online, or with your calculator, slide rule, Curta, or book.
Answer:
Around solar mass.
Explanation:
In a white dwarf, electron degeneracy prevents the star from collapsing into itself. However, if the mass of the star exceeds the Chandrasekhar Limit, gravity would overcome electron degeneracy and star would collapse further.
The value of the Chandrasekhar Limit is approximately ( times the mass of the sun.) While this mass is the maximum possible mass of a stable white dwarf, the original mass of the star that formed this white dwarf tends to be much greater.
1. Answer:
The relationship between Force A and Force B is given as:
A = B
Explanation:
To produce acceleration to a body, an unbalanced force must be applied. Meaning that a Force must be applied to the body greater than that of Force of Friction.
In our case, a Force A is exerted on the crate which is moving with a constant velocity. As there is no acceleration, the force applied must be equal to the force of Friction B.
2. Answer:
The electron's acceleration is 1.756 x 10¹⁷ ms⁻².
Explanation:
Electric field exerts a Force on the electron given as:
F = 1.6 x 10⁻¹³ N
Rest mass of electron = 9.11 x 10⁻³¹ kg
According to newton's 2nd law of motion, a net force F applied on the electron must produce an acceleration 'a' which is directly proportional to the Force and inversely proportional to the rest mass of the electron given as:
a = F/m
a = (1.6 x 10⁻¹³)/(9.11 x 10⁻³¹)
a = 1.756 x 10¹⁷ ms⁻²
Answer:
d) a = 4.1 m/s²
Explanation:
m = 92 Kg
∅ = 40º
μ = 0.293
a = ?
We can obtain the forces in the direction x' (of motion)
Wx' = W*Sin ∅ = m*g*Sin ∅
Ffriction = μ*N = μ*m*g*Cos ∅
then we use Newton's 2nd Law as follows:
Wx' - Ffriction = m*a
m*g*Sin ∅ - μ*m*g*Cos ∅ = m*a
⇒ a = g*(Sin ∅ - μ*Cos ∅)
⇒ a = (9.81 m/s²)*(Sin 40º - 0.293*Cos 40º)
⇒ a = 4.1038 m/s²