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sp2606 [1]
3 years ago
9

Convert time from 12-hour to 24-hour clock. ​

Physics
1 answer:
Kamila [148]3 years ago
6 0
22:54 is the answer you are looking for
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A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A
Kruka [31]

Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)=  800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

M\times 800 = ( M + m )\omega_f

3\times 800 = (3+1.1)\times \omega_f

2400 = (4.1)\times \omega_f

\omega_f = 585.37 \ rev/s

3 0
4 years ago
Light waves can be easily blocked but ______ waves pass through all substances? ( fill in the blank)
IRINA_888 [86]
Compressional waves can travel through all states of matter.
8 0
3 years ago
A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?​
Trava [24]

Answer:

23.49m

Explanation:

Distance =  velocity x time

8.7 x 2.7 = 23.49m

8 0
3 years ago
What is the resultant force on the human cannonball in the
Svetllana [295]

Answer:

heart

Explanation:

4 0
3 years ago
1. A small package is dropped from the Golden Gate Bridge. What is the velocity of the package
Sidana [21]

The velocity of the package  after it has fallen for 3.0 s is 29.4 m/s

From the question,

A small package is dropped from the Golden Gate Bridge.

This means the initial velocity of the package is 0 m/s.

We are to calculate the velocity of the package  after it has fallen for 3.0 s.

From one of the equations of kinematics for objects falling freely,

We have that,

v = u + gt

Where

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

and t is time

To calculate the velocity of the package  after it has fallen for 3.0 s

That means, we will determine the value of v, at time t = 3.0 s

The parameters are

u = 0 m/s

g = 9.8 m/s²

t = 3.0 s

Putting these values into the equation

v = u + gt

We get

v = 0 + (9.8×3.0)

v = 0 + 29.4

v = 29.4 m/s

Hence, the velocity of the package  after it has fallen for 3.0 s is 29.4 m/s

Learn more here: brainly.com/question/13327816

6 0
2 years ago
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