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alexgriva [62]
2 years ago
12

9. Steradian is the angel which lies in: a) One dimension b) Two dimensions

Physics
2 answers:
Marizza181 [45]2 years ago
8 0

Answer:

B

Explanation:

B

m_a_m_a [10]2 years ago
6 0

Answer:

<h2>Question:Steradian is the angel which lies in?</h2>

<h2>Answer:A.)<u>O</u><u>n</u><u>e</u><u> </u><u>d</u><u>i</u><u>m</u><u>e</u><u>n</u><u>s</u><u>i</u><u>o</u><u>n</u></h2><h2 />

Explanation:

<h2><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em></h2>

<em><u>a</u></em><em><u>d</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>i</u></em><em><u>e</u></em><em><u>s</u></em><em><u>t</u></em>

<em><u>5</u></em><em><u> </u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>r</u></em><em><u>s</u></em>

<h2><em><u>T</u></em><em><u>H</u></em><em><u>A</u></em><em><u>N</u></em><em><u>K</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em></h2>
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Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
salantis [7]

Explanation:

Mass of bumper cars, m_1=m_2=110\ kg

Initial speed of car A, u_1=8\ m/s

Initial speed of car Z, u_2=-10\ m/s

Final speed of car A after the collision, v_1=-10\ m/s

We need to find the velocity of car Z after the collision. Let it is equal to v_2. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

110\times 8+110\times (-10)=110\times (-10)+110v_2

v_2=\dfrac{-1320}{110}\ m/s

v_2=-12\ m/s

So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.

5 0
3 years ago
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Veseljchak [2.6K]

Answer:

The speed of q₂ is 4\sqrt{10}\ m/s

Explanation:

Given that,

Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

E_{i}=E_{f}

\dfrac{1}{2}mv_{i}^2+\dfrac{kq_{1}q_{2}}{r_{i}}=\dfrac{kq_{1}q_{2}}{r_{f}}+\dfrac{1}{2}mv_{f}^2

\dfrac{1}{2}m(v_{i}^2-v_{f}^2)=kq_{1}q_{2}(\dfrac{1}{r_{f}}-\dfrac{1}{r_{i}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{f}^2)=9\times10^{9}\times-2\times10^{-6}\times-8\times10^{-6}(\dfrac{1}{(0.4)}-\dfrac{1}{(0.8)})

0.00075(400-v_{f}^2)=0.18&#10;

400-v_{f}^2=\dfrac{0.18}{0.00075}

-v_{f}^2=240-400

v_{f}^2=160

v_{f}=4\sqrt{10}\ m/s

Hence, The speed of q₂ is 4\sqrt{10}\ m/s

7 0
2 years ago
Write down an example scenario of an object that has acceleration
Grace [21]

Answer:

An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.

if a car turns a corner at constant speed, it is accelerating because its direction is changing. The quicker you turn, the greater the acceleration. So there is an acceleration when velocity changes either in magnitude (an increase or decrease in speed) or in direction, or both.

Explanation:

5 0
2 years ago
Which of the following would cause the greatest decrease in gravitational force between the earth and the moon? an increase in t
Sphinxa [80]
<span>a decrease in the distance between the earth and the moon</span>
8 0
3 years ago
An athlete executing a long jump leaves the ground at a 28.0º angle and travels 7.80 m. (A) What was the takeoff speed?
Naddika [18.5K]

Answer:

9.6 m/s

Explanation:

Angle of projection, θ = 28°

Horizontal distance, R = 7.8 m

Let the velocity of projection is given by u.

The formula used to find the velocity of projection is given by

R=\frac{u^{2}Sin2\theta }{g}

7.8=\frac{u^{2}Sin\left (2\times 28  \right ) }{9.8}

7.8=\frac{u^{2}\times 0.829}{9.8}

u = 9.6 m/s

Thus, the velocity of projection is 9.6 m/s.

7 0
2 years ago
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