4 years ago

Sentence for pure substance

Physics

1 answer:

garri49 [273]4 years ago

8 0

Gold is a pure substance that can be found on the periodic table of elements.

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Which one is it i need this for my credit recovery

svlad2 [7]

I believe the answer is conduction.

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3 years ago

Car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver not

musickatia [10]

Answer:

Part A: $t = v_0/a_0$

Part B: $t = v_0/a_0$

Part C: $v_0^2/a_0$

Explanation:

Part A:

We will use the following kinematics equation:

$v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}$

Part B:

We will use the same kinematics equation:

$v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}$

Part C:

The total time takes is 2t.

So the train moves a distance of

$x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}$

And the car moves a distance in Part A and in Part B:

$d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}$

So the total distance that the car traveled is $d = \frac{v_0^2}{a_0}$

The difference between the train and the car is

$x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}$

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3 years ago

Combo Circuits VIR Charts. Can someone please fill this in?

Firlakuza [10]

Answer:

u need to explain more !!

Explanation:

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3 years ago

Caculate the acceleration of an airplane that goes from 0 knots to 400 knots in 8 seconds

mafiozo [28]

400 divided by 8 is 50, so its acceleration is 50 knots per second, meaning its speed is increasing by 50 every second.

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3 years ago

A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance fr

levacccp [35]

To calculate the horizontal distance traveled by the ball, we first calculate the total time it takes to reach the ground as follows:

t = √[2y/g] = <span>√[2(0.55) / 9.81]
t = 0.33 s

The horizontal distance would be

</span><span>X = Vx*t = 1.2*√[2*.55/9.8] = 0.4 m
</span>
Hope this helps.

4 0

3 years ago

Read 2 more answers