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3 years ago

What's 5 and 6? Physics

Physics

1 answer:

Elanso [62]3 years ago

4 0

10.2 m/s means in 1 sec he travels 10.2 metres. so in 20 sec he travels 20×10.2= 204 meters

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A ray of light traveling through air strikes a piece of diamond at an angle of incidence equal to 56 degrees. Calculate the angu

Montano1993 [528]

Answer:

The angle of separation is $\Delta \theta = 0.93 ^o$

Explanation:

From the question we are told that

The angle of incidence is $\theta _ i = 56^o$

The refractive index of violet light in diamond is $n_v = 2.46$

The refractive index of red light in diamond is $n_r = 2.41$

The wavelength of violet light is $\lambda _v = 400nm = 400*10^{-9}m$

The wavelength of red light is $\lambda _r = 700nm = 700*10^{-9}m$

Snell's Law can be represented mathematically as

$\frac{sin \theta_i}{sin \theta_r} = n$

Where $\theta_r$ is the angle of refraction

=> $sin \theta_r = \frac{sin \theta_i}{n}$

Now considering violet light

$sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}$

substituting values

$sin \theta_r__{v}} = \frac{sin (56)}{2.46}$

$sin \theta_r__{v}} = 0.337$

$\theta_r__{v}} = sin ^{-1} (0.337)$

$\theta_r__{v}} = 19.69^o$

Now considering red light

$sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}$

substituting values

$sin \theta_r__{R}} = \frac{sin (56)}{2.41}$

$sin \theta_r__{R}} = 0.344$

$\theta_r__{R}} = sin ^{-1} (0.344)$

$\theta_r__{R}} = 20.12^o$

The angle of separation between the red light and the violet light is mathematically evaluated as

$\Delta \theta = \theta_r__{R}} - \theta_r__{V}}$

substituting values

$\Delta \theta =20.12 - 19.69$

$\Delta \theta = 0.93 ^o$

6 0

4 years ago

PLEASE ASWR How heavy is the object if it takes 7N to push up a ramp that is 35m long and 9m high?

DiKsa [7]

Answer:

Explanation:

6 0

2 years ago

Read 2 more answers

Name 4 COARSE grained rocks

MrRa [10]

Answer:

Diorite, Gabbro, and Granite

Explanation:

8 0

3 years ago

Read 2 more answers

The metal gold crystallizes in a face centered cubic unit cell with one atom per lattice point. When X-rays with λ = 1.436 Å are

Umnica [9.8K]

Answer:

r = 1.45 Å

Explanation:

given,

λ = 1.436 Å

θ = 20.62°

d = a

n = 2

metal gold crystallizes in a face centered cubic unit cell

Radius of the gold atom = ?

using Bragg's Law

n λ = 2 d sin θ

2 x 1.436 Å = 2 a sin 20.62°

a = 4.077 Å

We know relation of radius for face centered cubic unit cell

$a = \dfrac{4r}{\sqrt{2}}$

$4.077= \dfrac{4\times r}{\sqrt{2}}$

r = 1.45 Å

the radius of a(n) gold atom. is equal to 1.45 Å

7 0

3 years ago

The displacement vector from your house to the library is 520 m long, pointing 40 ∘ north of east.What are the x-component (x-ax

Alexeev081 [22]

Answer:

398.3 m, 334.2 m

Explanation:

The magnitude of the displacement vector is

v = 520 m

And its direction is

$\theta=40^{\circ}$

measured as north of east.

The x-component of this vector is given by:

$v_x = v_0 cos \theta = (520)cos 40^{\circ}=398.3 m$

While the y-component is given by

$v_y = v_0 sin \theta =(520)sin 40^{\circ}=334.2 m$

7 0

3 years ago