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3 years ago

Which will reduce the possible environmental damage associated with mining uranium?

Physics

1 answer:

nignag [31]3 years ago

6 0

Answer:

Explanation:

Edge 2021

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8. A unit used to measure a vector quantity is the...... a) Second b) gram c) Newton d) Kilogram

kirill115 [55]

Answer:

Explanation:

A unit used to measure a vector quantity is the

c) Newton

3 0

1 year ago

A ball is thrown up onto a roof, landing 4 sec later at height of 20m above the release level. The balls path just before landin

Kobotan [32]

<span>c) what is the angle (relative to the horizontal) of the balls initial velocity? </span>

8 0

3 years ago

6th grade science I mark as brainliest.

DerKrebs [107]

Answer:

2m 13 $\frac{1}{3}$ s

Explanation:

1.5m = 1s

200m = $\frac{200}{1.5}$ × 1s

= 133 $\frac{1}{3}$ s

= 2m 13 $\frac{1}{3}$ s

3 0

2 years ago

A rock is dropped from a helght of 2.5 meters. What is its velocity when it reaches the ground?

Nataly_w [17]

u=0 m/s

h=2.5m

Using kinematic eq:

${v}^{2} - {u}^{2} = 2gh \\ {v}^{2} - {0}^{2} = 2gh \\ v = \sqrt{2gh} \\ v = \sqrt{2 \times 10 \times 2.5} \\ v = \sqrt{50} \\ v = 7.07m/s$

7 0

3 years ago

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi

alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha t$

Put the value into the formula

$5.0-0=\alpha\times8.0$

$\alpha=\dfrac{5.0}{8.0}$

$\alpha=0.625\ rev/s^2$

We need to calculate the angular displacement

Using equation of angular motion

$\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta=0+\dfrac{1}{2}\times0.625\times(8.0)^2$

$\theta=20\ rev$

Now, The washer coming to rest from top spin

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha t$

$\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}$

$\alpha=\dfrac{0-5}{12}$

$\alpha=−0.4167\ rev/s^2$

We need to calculate the angular displacement

Using formula of displacement

$\theta'=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta'=5\times12+\dfrac{1}{2}\times(-0.4167)\times12^2$

$\theta'=30\ rev$

We need to calculate the total number of revolution

$\theta''=\theta+\theta'$

$\theta''=20+30$

$\theta''=50\ rev$

Hence, The total number of revolution is 50 rev.

5 0

3 years ago