Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
Hey You!
Ten to the power of two = 100
So, when 42.6 is divided by 100, Sue should move the decimal 2 places to the left (before the 4).
42.6 ÷ 100 = 0.426
Answer:
The answer to your question is y = 4/3x + 1/3
Step-by-step explanation:
Data
Point A = (2, 3)
Point B = (5, 7)
Process
1.- Calculate the slope
x1 = 2 y1 = 3
x2 = 5 y2 = 7
m = (y2 - y1)/(x2 - x1)
- Substitution
m = (7 - 3)/(5 - 2)
- Slope
m = 4/3
2.- Find the equation of the line
y - y1 = m(x - x1)
y - 3 = 4/3(x - 2)
y - 3 = 4/3x - 8/3
y = 4/3x - 8/3 + 3
y = 4/3x - 8/3 + 9/3
y = 4/3x + 1/3
