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aniked [119]
3 years ago
8

ANSWER QUICK!!

Mathematics
2 answers:
netineya [11]3 years ago
5 0

Answer: Divide 2 by 6- 0.3 with a bar over the 3,    Step-by-step explanation: 0.3 with a bar over the 3 is the decimal form of 2/6

snow_lady [41]3 years ago
5 0
Divide 2 by 6 because it’s 2/6.
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For his long distance phone service, Keith pays a $3 monthly fee plus 11 cents per minute. Last month, Keith's long distance bil
Allushta [10]

The number of minutes for which Keith was billed = 97

Step-by-step explanation:

Step 1:

It is given that Keith pays a fixed fee of 3$ a month and 11 cents per minute  for the number of minutes used.

Total cost = Fixed cost + Per minute cost

If x represents the number of minutes consumed in a month then we can compute the total cost using the below equation:

Total cost = 3$ + 0.11 * x

Step 2:

The total cost is 13.67$

Substituting in the equation we get

13.67 = 3 + 0.11 * x

x = 10.67 / 0.11 = 97 minutes

Step 3:

Answer:

The number of minutes for which Keith was billed = 97

3 0
3 years ago
13. The pair of figures are congruent. Find the value of e.
Sergio [31]

Answer:

No solution is possible from the provided information

Step-by-step explanation:

3 0
3 years ago
19. passes through (1, 4) and (-1, 1)
galina1969 [7]
Ok so the answer to this was a bit tricky but it is 1,8
7 0
3 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
Urn I contains 2 red balls and 2 white balls. Urn II contains 13 white balls. A ball is selected at random from urn I and placed
beks73 [17]
15/17 Because there is a 13/13 chance but then you put a ball in from Urn 1 and that is 2/4. Also, 13/13 plus 2/4 = 15/17
6 0
3 years ago
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