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svet-max [94.6K]
3 years ago
8

Find the common ratio of the sequence -164, -82, -41, -20.5

Mathematics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

r = \frac{1}{2}

Step-by-step explanation:

The common ratio r of a geometric sequence is

r = \frac{a_{2} }{a_{1} } = \frac{a_{3} }{a_{2} } = \frac{a_{4} }{a_{3} } = ......

r = \frac{-82}{-164} = \frac{-41}{-82} = \frac{1}{2}

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Sally's soccer team played 25
pantera1 [17]

Answer:

64%

Step-by-step explanation:

25 - 9 = 16, so 16 of the games were won by Sally's team.

16/25 = 64% of the games were won

6 0
2 years ago
Find the discriminant of the following quadratic equation then state the number of rational, irrational, and imaginary solutions
lianna [129]

Answer:

  • -6x² - 6 = -7x - 9
  • -6x² + 7x - 6 + 9 = 0
  • -6x² + 7x + 3 = 0
  • 6x² - 7x - 3 = 0

<u>Discriminant:</u>

  • D = (-7)² - 4*6*(-3) = 49 + 72 = 121

<u>Since D > 0, there are 2 real solutions:</u>

  • x = (- (-7) ±√121 )/12
  • x = (7 ± 11)/12
  • x = 1.5, x = -1/3

8 0
3 years ago
Read 2 more answers
The formula for the volume of a cone is v=1/3pir^2h. Find the radius, to the nearest hundredth, of a cone with a height of 3 in.
Maru [420]
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
radius^2 = (3 * Volume) / (PI * height)
</span></span></span></span><span>radius^2 = (3 * 12) / (PI * 3)
radius^2 = (36)/ (</span><span>9.4247779608) </span><span>
radius^2 = </span> <span> <span> <span> 3.8197186342 </span> </span> </span>
radius = <span> <span> <span> 1.95</span></span></span>




7 0
3 years ago
What are some solution(s) to the quadratic equation 40 - x^2 = 0
Serhud [2]

Answer:

x = ± 2\sqrt{10}

Step-by-step explanation:

given

40 - x² = 0 ( add x² to both sides )

40 = x² or

x² = 40 ( take the square root of both sides )

x = ± \sqrt{40} = ± \sqrt{4(10)} = ± 2\sqrt{10}

3 0
3 years ago
Solve the problem. Use 3.14 for 4072-07-02-02-00_files/i0170000.jpg, and round your answer to the nearest tenth.
nalin [4]
Volume= (3.14)r^2h
Volume= 3.14 (9.5)^2 5
Volume= 1416.9 ft^3
7 0
3 years ago
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