Answer:
0.00002 = 0.002% probability of actually having the disease
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Positive test
Event B: Having the disease
Probability of having a positive test:
0.05 of 1 - 0.000001(false positive)
0.99 of 0.000001 positive. So

Probability of a positive test and having the disease:
0.99 of 0.000001. So

What is the probability of actually having the disease

0.00002 = 0.002% probability of actually having the disease
Answer: 5x+2y=2
Step-by-step explanation:
5x+2y=2 move 5x to the other side
2y=-5x+2 divide the other side by the 2 from 2y
y=-5x+1
Answer:
-15/41
Step-by-step explanation:
-3x + 15 - 6x = 30 + 32x
~Combine like terms
-9x + 15 = 30 + 32x
~Subtract 15 to both sides
-9x = 15 + 32x
~Subtract 32x to both sides
-41x = 15
~Divide -41 to both sides
x = -15/41
Best of Luck!
Answer:
23
Step-by-step explanation:
Answer:749.642
Step-by-step explanation: