If the side of square P is x and the side of square Q is y, we have x+y=26. In addition, 3*the perimeter of P+8*4y=3*4x+32y=12x+32y=492.
We have
x+y=26
12x+32y=492
Multiplying the first equation by -12 and adding it to the second, we get
20y=180 and dividing by 20 we get y=9. Plugging it into the first equation, we get 26-9=17=x. Since the area of square P is x^2 and Q is y^2,
x^2+y^2=19^2+7^2=410=the sum of the squares
Answer:
a is x>3
b is _> x/4 +12
c is x>-3
Step-by-step explanation: hope this helps
Answer:
b = -1/10.
Step-by-step explanation:
(2i/2+i)-(3i/3+i)
= 2i(3 + i) - 3i(2 + i) / (2 + i)(3 + i)
= 6i + 2i^2 - 6i - 3i^2 / (2 + i)(3 + i)
= (-2 + 3) / (6 + 5i - 1)
= 1 / (5 + 5i)
Now we multiply top and bottom by 5 - 5i :
= 5 - 5i / (5 + 5i)(5 - 5i)
= 5 - 5i / 25 -25i^2
= 5 - 5i / 50
= 1/10 - 1/10i
