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Slav-nsk [51]
3 years ago
14

The following sample of weights was taken from 8 cookies off the assembly line. Construct the 95% confidence interval for the po

pulation variance for all cookies that come off the assembly line. Round your answers to two decimal places.
9.6,10.2,10.3,9.2,9.5,10.1,9.2,9.4
Mathematics
1 answer:
Gemiola [76]3 years ago
8 0

Answer:

what are you asking

Step-by-step explanation:

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Evaluate the expression 10^2+(3+5)^2 - 5=
vampirchik [111]

Answer:

159

Step-by-step explanation:

10^2+(3+5)^2-5

-> 100 + (3+5)^2 -5

-> 100 + 8^2 - 5

-> 100 + 64 - 5

-> 159

8 0
2 years ago
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Complete the square: x2 - 6x + Blank = -13 + Blank​
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Answer:

x^2 - 6x + 9 = (x-3)^2

Step-by-step explanation:

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2. Explain how the number of edges for the rectangular
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Greg deposited $4000 into an account with 4.6% interest, compounded semiannually. Assuming that no withdrawals are made, how muc
Zinaida [17]

The amount in account after 7 years is $ 5499.445

<em><u>Solution:</u></em>

<em><u>The formula for total amount in compound interest is given as:</u></em>

A = p(1+\frac{r}{n})^{nt}

A = the future value of the investment/loan, including interest

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

Here given that,

A = ?

P = 4000

t = 7 years

r = 4.6 \% = \frac{4.6}{100} = 0.046

n = 2 ( since compounded semi annually)

<em><u>Substituting the values in formula, we get</u></em>

A = 4000(1+\frac{0.046}{2})^{2 \times 7}\\\\Simplify\ the\ above\ expression\\\\A = 4000(1+0.023)^{14}\\\\A = 4000(1.023)^{14}\\\\A = 4000 \times 1.37486\\\\A = 5499.445

Thus amount in account after 7 years is $ 5499.445

4 0
4 years ago
Wich answer is not an example of a primary source?​
aleksley [76]
What are the answer choices?
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3 years ago
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