Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
m∠A ≈ 43°
m∠B ≈ 55°
mBC ≈ 20
Step-by-step explanation:
Law of Sines: 
Step 1: Find m∠B

Step 2: Solve for ∠B
29sinB = 24sin82°
sinB = 24sin82°/29
B = sin⁻¹(24sin82°/29)
B = 55.038°
Step 3: Find m∠A
180 - (55.038 + 82)
180 - 137.038
m∠A = 42.962°
Step 4: Find BC

Step 5: Solve for BC
29sin42.962° = BCsin82°
BC = 29sin42.962°/sin82°
BC = 19.9581
Answer:

Step-by-step explanation:

Answer:
13 students were fed
Step-by-step explanation:
now first in order to count we will have to turn 3 1/4 into a whole number which means we will have to multiply the denomintor by 3 and add it to the numerator which is 1
4 x 3= 12 ..... 12 + 1 = 13
13/4 and the denominator always stays the same
and now to count we will have to divide 13/4 divided by 1/4
now instead of dividing you can just multiply them by switching the denominator and numerator 1/4 to 4/1
13/4 x 4/1
52/4
13