now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5Cdotfill%20%26%20%5C%244000%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B18%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%204000%3DP%5B1%2B%280.05%29%28%5Cfrac%7B3%7D%7B2%7D%29%5D%5Cimplies%204000%3DP%281.075%29%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B4000%7D%7B1.075%7D%3DP%5Cimplies%203720.93%5Capprox%20P)
we have that
<span>three and one-tenth------> 3 1/10--------> (3*10+1)/10--------> 31/10-----> 3.1
the answer is 3.1 ml</span>
Answer:
9
Step-by-step explanation:
n2-27=6n
Than n (exponet) 2 - 27 - 6n = 0
Now factor (n-9)(n+3)=0
Answer:
SinL = 7/25
CosL = 24/25
TanL = 7/24
Step-by-step explanation:
Find the diagram attached.
Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL
Note that the hypotenuse is the longest side = 25
The opposite will be the side facing the acute angle L
Opposite = 7
Adjacent = 24
For SinL
sinL = Opposite/Hypotenuse {SOH}
SinL = 7/25
For cosL:
CosL = Adjacent/Hypotenuse{CAH}
CosL = 24/25
For tanL:
TanL = Opposite/Adjacent {TOA}
TanL = 7/24
Answer:
76 degrees
Step-by-step explanation:
find angle 5 by subtracting 76 from 180 to get 104 degrees
the find angle 7 by subtracting 104 from 180 to get 76
180-76 =104
180-104=76