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tekilochka [14]
2 years ago
12

The two roots a+sqrb and a-sqr b are called _______radicals.

Mathematics
1 answer:
astraxan [27]2 years ago
6 0

Answer:

Conjugate radicals.

Step-by-step explanation:

The two roots a+sqrb and a-sqr b are called conjugate radicals.

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<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
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<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
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<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
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</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

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sin2x- cos2x=2sinxcosx-1+2(sinx)^2

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