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2 years ago

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The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. after 3 hours

it is observed that 600 bacteria are present. after 10 hours 4000 bacteria are present. what was the initial number of bacteria? (round your answer to the nearest integer.)

1 answer:

jeka57 [31]2 years ago

3 0

Ten thousand I believe let me know if wrong that’s what my math got

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soldi70 [24.7K]

Answer: 5x

Step-by-step explanation:

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Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin

Anastasy [175]

Suppose $y_2(x)=y_1(x)v(x)$ is another solution. Then

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Let $u(x)=v'(x)$ , so that

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$\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0$

Integrate both sides with respect to $x$ :

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2 years ago

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3 years ago

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kifflom [539]

Using an exponential function, it is found that it will take 24 years for the current population of 4800 deer to reduce to 600.

<h3>What is an exponential function?</h3>

An exponential function is modeled by:

$y = ab^x$

In which:

a is the initial value.

b is the rate of change, as a decimal.

In this problem, considering the initial value of 4800, and that the population halves every 8 years, the equation is given by:

$A(t) = 4800\left(\frac{1}{2}\right)^{\frac{t}{8}}$

The population will be of 600 when A(t) = 600, hence:

$A(t) = 4800\left(\frac{1}{2}\right)^{\frac{t}{8}}$

$600 = 4800\left(\frac{1}{2}\right)^{\frac{t}{8}}$

$\left(\frac{1}{2}\right)^{\frac{t}{8}} = \frac{600}{4800}$

$\left(\frac{1}{2}\right)^{\frac{t}{8}} = \frac{1}{8}$

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Hence:

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It will take 24 years for the current population of 4800 deer to reduce to 600.

More can be learned about exponential functions at brainly.com/question/25537936

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