Basically we need to add and subtract 1/2 from 1/6:
(1) 1/6 - 1/2 = 1/6 - 3/6
= -2/6
= -1/3
(2) 1/6 + 1/2 = 1/6 + 3/6
= 4/6
= 2/3
Therefor the two numbers that are located 1/2 unit from 1/6 are -1/3 and 2/3
Answer:
a) h'(t)= (6cos3t,-9sin3t,3
cos3t)
b) t=0.93994736+πn/3
c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere
Step-by-step explanation:
D = 390mi
r = 60 mi/h
390/60 = 6.5
(t) = 6.5 h
34
16^2 = 256
30^2 = 900
900+256 = 1156
square root of 1156 = 34