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Tema [17]
3 years ago
11

BRAINLIESTTT ASAP! PLEASE HELP ME :) Find the inverse of :

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0

Answer:

\displaystyle h^{-1}(x) = 2\frac{1}{2}x - 3

Step-by-step explanation:

\displaystyle y = \frac{2x + 6}{5} → x = \frac{2y + 6}{5} \\ \\ 5x = 2y + 6

5x = 2y + 6

- 6 - 6

_________

\displaystyle \frac{-6 + 5x}{2} = \frac{2y}{2} \\ \\ -3 + 2\frac{1}{2}x = y → h^{-1}(x) = 2\frac{1}{2}x - 3

I am joyous to assist you anytime.

muminat3 years ago
5 0

Answer:

h^{-1}(x) = \dfrac{5x - 6}{2}

Step-by-step explanation:

h(x)= \dfrac{2x + 6}{5}

(a) Rename h(x) as y  

y = \dfrac{ 2x+ 6}{5}

(b) Solve for x :  

\begin{array}{rcl}y& = &\dfrac{2x + 6}{5}\\\\5y & = & 2x + 6\\5y - 6 & = & 2x\\x & = & \mathbf{\dfrac{5y - 6}{2}}\end{array}

(d) Switch x and y  

y = \dfrac{5x -6}{2}

(e) Rename y as the inverse function  

h^{-1}(x) = \mathbf{\dfrac{5x - 6}{2}}

The graphs of inverse functions are reflections of each other across the line y = x.

In the diagram, the graph of h⁻¹(x) is the reflection of h(x) about the line y = x.

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John leaves his home. He travels 5 blocks south and three blocks west. As the crow flies, how far is John from his home?
riadik2000 [5.3K]

Answer:

5.83 blocks away from his home

Step-by-step explanation:

If he travels 5 blocks south and 3 blocks west, the distance from his house considered along with the distances travelled gives a right angled triangle whose opposite side and adjacent sides are the distances travelled north and west.

The distance from his house after moving 3 blocks west is the hypotenuse side. As such, the distance may be computed using Pythagoras' theorem. Let the distance from his house be G

G^2 = 5^2 + 3^2

G^2 = 25 + 9

= 34

G = √34

=5.83

John is 5.83 blocks away from his home

3 0
3 years ago
PLEASE HELP
max2010maxim [7]

Hello!


So, this is quite the complex question, and here are the following steps:


What is the quotient of \frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}?

\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (rationalize the denominator)

\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

5 0
3 years ago
What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b
kramer

Option C: a=3, b=4 is the value of a and b

Explanation:

Given that the expression \sqrt{648}=\sqrt{2^a\times3^b}

We need to determine the value of a and b

Let us consider the term \sqrt{648} and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

648=2 \cdot 324

324 divides by 2,

648=2 \cdot 2 \cdot 162

162 divides by 2,

648=2 \cdot 2 \cdot 2 \cdot 81

81 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27

27 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9

9 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3

Thus, we have,

\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}

Therefore, equating the powers of 2 and 3, we get,

a=3, b=4

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0
3 years ago
Read 2 more answers
Hallie is helping put away dishes in the school cafeteria . She is stacking bowls to put into the cupboard. If she has 62 bowls
aliina [53]

The minimum number of Halle will have 15 stacks.

3 0
3 years ago
Read 2 more answers
Can somebody help me with this please
Hitman42 [59]
Eleven is the sum. Add end is 7 and the ones is 4
3 0
3 years ago
Read 2 more answers
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