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Artyom0805 [142]
3 years ago
10

Solve the system of equations by graphing where f(x)=5-2x and g(x)=(2/3)x-2. What is the value of x? 0 1 2 3 4

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

The graph is uploaded in the attachment.

The value of x is 2.625.

Step-by-step explanation:

  • let us plot f(x), g(x) on y-axis

so, f(x)=y and g(x)=y.

  • the first equation can be written as y=5-2x
  • the general equation of a straight is y=mx+c

( where m is the slope and c is the y-intercept )

  • now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
  • the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
  • now plot the graph using above information.

(y-intercept is the the coordinate of a point where the line intersects y-axis)

(slope is the angle made by the line with the x-axis)

  • by seeing the graph, the value of x is 2.625.

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-22x +3x/ 3x + 7 =2 what is my first step
aleksandr82 [10.1K]

Answer:

-22x +3x/ 3x =2-7

Step-by-step explanation:

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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
zalisa [80]

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

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n= nth position

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d= a2-a1

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Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

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\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

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\displaystyle\int_{\mathcal C}\cos x\sin y\,\mathrm dx+\sin x\cos y\,\mathrm dy=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(\frac{3\pi}2,\frac\pi2\right)-f(0,-\pi)=-1
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A storekeeper has two kinds of flour, one selling for 65 cents per pound, and the other selling for 95 cents per pound. How many
Murrr4er [49]

Answer:

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Step-by-step explanation:

Let

x ----> amount of 65 cents per pound flour to use

y----> amount of 95 cents per pound flour to use

we know that

x+y=100 ----> y=100-x ----> equation A

0.65x+0.95y=0.83(100) ----> equation B

substitute equation A in equation B

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therefore

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4 0
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