Answer:
I did and I must say I don't know what I was expecting but he deserved it.
Answer:
1)
Part l: N+5
Part ll: 4+3 - 3
Part lll: x/2 - 7
Part lV: 5-4(m)
2)
Part l: 6(x)= 22
Part ll: 2(n) +7 = 19
Part lll: t^2 - 3 = 46
Part IV: m:n -2 =10
3)
Part l: $400
Part ll:
week 0-220
week 1-140
week 2-170
week 3-200
week 4-230
Part lll: W/2 = m
Part IV: $640- to show your work just add $60 to each week
4)
$96 - $48= $48= CD player
This is a guess, but, from what I've researched, maybe decrease? I've looked into it alot and that's just I think, though, it may depend on the previous height. Still, just an educated guess (I've got 100% on all kinds of quizzes because of educated guesses so, it may work!)
For example,area = a, length = l, width = w
First we write two equations. The easier equation is the area equation, which we know to be
a = l x w
So that the first equation is :
<span>96 = l x w </span>
we make the second equation of the following statements :
<em>The length of a rectangle is 2 foot less than 3 times its width.</em>
<span>so it becomes :
l = 3w - 2
</span>
<span>To solve, we can use the substitution method.
</span>
![96 = l \times w\\96=(3w-2) \times w\\96=3w^{2}-2w\\3w^{2}-2w-96=0~~~~~~[now\ factor\ the\ equation]\\ (3w+16)(w-6)=0](https://tex.z-dn.net/?f=96%20%3D%20l%20%5Ctimes%20w%5C%5C96%3D%283w-2%29%20%5Ctimes%20w%5C%5C96%3D3w%5E%7B2%7D-2w%5C%5C3w%5E%7B2%7D-2w-96%3D0~~~~~~%5Bnow%5C%20factor%5C%20the%5C%20equation%5D%5C%5C%20%283w%2B16%29%28w-6%29%3D0)


<span><em>So if our width is 6, Now substitute the value of w = 6 into equation 2 </em></span>
So "w" = 6 and "l" = 16, and if we multiply them together, we get the correct area, 96. So our dimensions are 6 by 16.