B it is going to give you the answer
How am i supposed to draw it ??
From what you said the choices go up by 3 every time in different combinations . Its at least 36 or more combinations .
i did my best guess from the choice .. hope it helps
The empirical probability of a 4 or 5 is
(count of outcome = 4 or 5)/(count of all outcomes) = (44 +40)/240 = 7/20
The problem statement asks you to assume the outcomes will remain in this proportion going forward. That is, the number of outcomes (n) of 4 or 5 in the next 60 rolls of the number cube is expected to satisfy
7/20 = n/60
Multiplying that by 60 gives
n = 60*(7/20) = 21
Selection D is appropriate.
Answer:
48 days
Step-by-step explanation:
Given that :
Sumiko runs bleachers every 6 days
Jandella runs bleachera every 16 days
The soonest they will see each other again is in days can be obtained by getting the lowest common multiple of 6 and 16
Multiples of
6 : 6, 12, 18, 24, 30, 36, 42, 48, 54,...
16 : 16, 32, 48, 64,...
Lowest common multiple of 6 and 16 = 48
Hence, the soonest they'll see each other again is in 48 days
