Answer:
Part 1) The unit rate is
Part 2) A 56 ounce bag of pumpkin Seeds cost $14.00
Step-by-step explanation:
Part 1) What is the unit rate for the pumpkin seeds?
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
Let
y ----> the cost of pumpkin seeds in dollars
x ---> the weight in ounces
we have
For x=24 ounces, y=$6
Find the value of the constant of proportionality k
substitute the values
The unit rate is the same that the constant of proportionality k
therefore
The unit rate is
Part 2) How much would 56.
ounce bag of pumpkin seeds cost?
we know that
The linear equation is equal to
For x=56 ounces
substitute in the linear equation and solve for y
(12x-14)-(3x+9)-(-4-1)
= 9x-18
12x-3x=9x
-14-9+4+1=-18
*Subtracting a group of numbers in parenthesis is the same as -1 times what every is in the parenthesis.
So it would be (12x-14)+(-3x-9)+(4+1)... which makes the equation alot easier to simplify.
Step-by-step explanation:
50% is basically half. So if you double the price ($2.25) x 2 you will have your answer.
So the answer is $4.50..!
Answer:
1. are you serious to ask ? it is written right there in the question itself. x=0, f(0)=y=6
2. the slope is 3
3. -4/3
4. $1.50 per book
5. -2
Step-by-step explanation:
1. the table itself says it for x=0. f(x) for x=0 is 6.
2. as explained do often already. the slope is the ratio of y/x showing how many units y changes, when x changes a unit or another surviving number of units.
the table shows when x increases by 1 unit, y increases by 3 units. so, the slow is 3/1 or simply 3.
3. again slope (see 2.).
going from M to N x increases by 4 units (from 1 to 5), and y decreases by 3 units (from 3 to 0).
so, the slope is y changes / x change = 4/-3 or simply -4/3
4. rate of change is
(f(a) - f(b)) / (a - b)
e.g.
(275 - 50) / (250 - 100) = 225 / 150 = 1.5
5. again very simple. which of the provided answer options appears in the f(x) column ?
the result of a function is the functional or y value calculated by the formula when responding the generic variable (like x) by the specified input value.