Step-by-step explanation:
4x^2-9
=(2x)^2 -3^2
=(2x+3) (2x-3)
Hope this helps you.
 
        
             
        
        
        
Oh Foxy, Foxy, how totally debilitated you must be !  Try to relax.  Nobody 
enjoys a painful brain, and believe me, this problem is not worth it.
Let me put it to you this way:  What if the problem said . . .
-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?
If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .
That's <em>almost </em>exactly what the problem <em>does</em> say.  
Except it doesn't say he has "$8 more than his sister", 
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that. 
Surely you can handle it from here, even with half of your brain 
tied behind your back.
Take a good hard look at ' A ', and then go lie down.
        
             
        
        
        
Answer:
Correct option: first one -> y = (1/3)x + (10/3)
Step-by-step explanation:
The linear function that represents a line is:
y = ax + b
Where a is the slope and b is the y-intercept.
First we need to find the slope of the line that goes through (0, -3) and (3, -2).
Using both points, we can find the equation of the line:
x = 0 -> y = -3
-3 = a*0 + b
b = -3
x = 3 -> y = -2
-2 = 3a - 3
3a = 1
a = 1/3
The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:
y = (1/3)x + b
The parallel line goes through the point (-4, 2), so we have:
x = -4 -> y = 2
2 = (1/3)*(-4) + b
b = 2 + (4/3)
b = 10/3
So the equation of the parallel line is:
y = (1/3)x + (10/3)
Correct option: first one
 
        
             
        
        
        
Answer:
Any equation of the form
y = kx + b, 
with b different from zero
Step-by-step explanation:
For example
y = 5*x +3
cannot be written in the form
y = k*x, because there is a term that shifts the graph upwards.