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Artyom0805 [142]
3 years ago
5

The earth's worst mass extinction was:

Physics
2 answers:
Ronch [10]3 years ago
7 0
<span>The Permian–Triassic (P–Tr) extinction event, colloquially known as the Great Dying, the End ...... Jump up ^ St. Fleur, Nicholas (16 February 2017). "After Earth's Worst Mass Extinction, Life Rebounded Rapidly, Fossils Suggest". New York Times ...</span><span>

</span>
Volgvan3 years ago
4 0

Permian-Triassic ..........................................................

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The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the10-g bullet is traveling at 300m/swhe
WARRIOR [948]

Answer:

6.8 mm

Explanation:

We are given that

Mass of block,m=10 kg

Mass of bullet,m_b=10 g=10\times 10^{-3} kg

1 kg=1000 g

Total mass of system,M=m+m_a=10+10\times 10^{-3}=10.01kg

Speed of bullet,u=300 m/s

\theta=30^{\circ}

By law of conservation of momentum

m_bucos\theta=Mv

v=\frac{m_bvcos\theta}{M}=\frac{0.01\times 300cos30^{\circ}}{10.01}=0.259m/s

According to law of conservation of energy

Change in kinetic energy of system=Change in potential energy of system

\frac{1}{2}Mv^2-0=Mgh-0

\frac{1}{2}(10.01)(0.259)^2=10.01\times 9.8 h

Where g=9.8 m/s^2

h=\frac{(0.259)^2}{2\times 9.8}=0.0034m

1m=100 cm

h=0.0034\times 100=0.34 cm

Distance traveled by block=d=\frac{h}{sin\theta}=\frac{0.34}{sin30^{\circ}}=0.68 cm=6.8 mm

1cm=10 mm

4 0
4 years ago
Is 53cm bigger than 5m?
Afina-wow [57]
Yes its bigger than 5 millimeters
3 0
3 years ago
Read 2 more answers
What is the force required to produce to produce a current of one ampere through a resistance of one ohm?
RoseWind [281]
1 Newton of force is required to produce that.....
8 0
4 years ago
A car that is standing still accelerates up a hill with a slope of 6.4% at an average acceleration of 2.93 ft/s^2. The hill is 1
alexgriva [62]

Answer:

213 s

Explanation:

Slope is the ratio of change in vertical distance to change in horizontal distance.

Slope = vertical height / horizontal height

Therefore:

6.4% = vertical height / 12.42

vertical height = 6.4% * 12.42

vertical height = 0.8 miles

The distance travelled by the car (s) is:

s² = 0.8² + 12.42²

s² = 154.9

s = 12.45 miles

Acceleration (a) =  2.93 ft/s^2 = 0.00055 mile/s²

initial velocity (u) = 0, final velocity = 203 mph

Using:

s = ut + 0.5at²

12.45 = 0.5(0.00055)t²

t =213 s

5 0
3 years ago
3. How much work is done when you pull a 6 N wagon for 5 meters?
8090 [49]

Answer:

<h2>30 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 6 N

distance = 5 m

We have

workdone = 6 × 5 = 30

We have the final answer as

<h3>30 J</h3>

Hope this helps you

3 0
3 years ago
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