Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.
I’m pretty sure it just wants you to list the property’s meaning the material and density
The circuit was installed in UF cable which requires a minimum burial depth of 6 inches for this circuit.
<h3>
UF cable</h3>
UF cable is used as an underground feeder cable to distribute power from an existing building to outdoor equipment. UF cable can also be used as direct burial cable.
For the 24-volt branch circuit installed, the minimum burial depth will be 6 inches.
Thus, the circuit was installed in UF cable which requires a minimum burial depth of 6 inches for this circuit.
Learn more about UF cable here: brainly.com/question/8591560
The number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
<h3>How to convert mass?</h3>
According to this question, caffeine concentration is 1.99 mg/oz.
1.99 milligrams can be converted to grams as follows:
1.99milligrams ÷ 1000 = 0.00199grams
This means that 0.00199grams per oz is the caffeine concentration.
If there were 12 oz in a can, then, 0.00199grams × 12 = 0.02388 grams in 1 can.
This means that if 10grams is considered lethal, 10grams ÷ 0.02388 grams = 419 cans would be lethal for consumption.
Therefore, the number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
Learn more about conversion factor at: brainly.com/question/14479308
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Moving an object up an inclined plane<span> requires </span>less<span>force </span>than<span> lifting it straight up, at a cost of an increase in the distance moved. The </span>mechanical advantage<span>of an </span>inclined plane<span>, the factor by which the force is reduced, is equal to the ratio of the length of the sloped surface to the height it spans.</span>
