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Flauer [41]
3 years ago
10

At a county fair, 9 people out of 1,000 earned a perfect score in a carnival game. What decimal represents the number of people

who earned a perfect score?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

Decimal represents the number of people who earned a perfect score is 0.009 .

Step-by-step explanation:

As given

At a county fair, 9 people out of 1,000 earned a perfect score in a carnival game.

Number\ of\ people\ who\ earned\ a\ perfect\ score = \frac{People\ who\ earned\ perfect\ score}{Total\ number\ people}

people who earned a perfect score = 9

Total number of people = 1000

Put in the above

Number\ of\ people\ who\ earned\ a\ perfect\ score = \frac{9}{1000}

Number of people who earned a perfect score = 0.009

Therefore  decimal represents the number of people who earned a perfect score is 0.009 .

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A group of preschoolers has 15 boys and 12 girls. What is the ratio of girls to boys.Also pls show me how u get it.​
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Answer:

12:15

Step-by-step explanation:

girls:boys

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105.6% in decimal form
anastassius [24]

To turn 105.6% into a decimal, we can remove the percent sign and divide by 100.

105.6 ÷ 100 = 1.056

Therefore, 105.6% can be written as the decimal 1.056.

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4[5(x + 3) - 2] + 3(x - 1)
Inessa [10]

Answer:

23x + 49

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4 (5x+15-2)+3x-3

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23x+52-3

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An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
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