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Vaselesa [24]
3 years ago
5

Low grades ore are less desirable than a high grade ores because?

Chemistry
1 answer:
wolverine [178]3 years ago
8 0
This is because a higher grade will result in a higher GPA which can help people get into college and even help them get scholarships. Lower grades will prevent you from getting into a good college and from getting scholarships. Higher grades an also result in free things! Car insurance rates go lower for kids with better grades/ a higher GPA.
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The state of the neuron when not firing a neural impulse is known as the _______________ _______________.
Fed [463]

Answer:Referring to the fact that a neuron either fires completely or does not fire at all.

Explanation:

6 0
2 years ago
Can sedimentation and decantation be used for all types of mixtures? Explain
Bumek [7]

Explanation:

1. Sedimentation and decantation cannot be used for all types of mixtures.

Decantation is a separation technique in which is used to separate immiscible liquids or mixtures containing liquid and solids within them.

In decantation, gravity is used to bring the denser materials to settle at the bottom.

For homogenous mixtures, it is not possible to use decantation. A solution of sugar and water will not decant.

2. Yes, mass of an object reduces the settling time of such object in a mixture.

The higher the mass, the faster the rate of settling. Also, as we know, mass is directly proportional to density. A body with a high density will settle faster in solution.

4 0
3 years ago
Help me on this question esplain
son4ous [18]

Answer:

They have the same number of valence electrons (5) so the body assumes they are the same element.

3 0
3 years ago
Values for the molar mass of nitrogen, oxygen, and nitrogen dioxide
CaHeK987 [17]

Answer:

n=N/Na

n =  \frac{8.23 \times {10}^{22} }{6.02  \times {10}^{23} }  = 0.1367 \: mol

answer: 0.14 mol

Explanation:

5 0
3 years ago
A researcher studying the nutritional value of a new candy places a 4.90 g sample of the candy inside a bomb calorimeter and com
snow_lady [41]

Answer:

449730.879 cal/g

Explanation:

Given data:

Mass of sample = 4.9 g

Change in temperature  = 2.08 °C  (275.23 k)

Heat capacity of calorimeter = 33.50 KJ . K⁻¹

Solution:

C(candy) = Q/m

Q = C (calorimeter) × ΔT

C(candy) = C (calorimeter) × ΔT / m

C(candy) =  33.50 KJ . K⁻¹ × 275.23 K / 4.90 g

C(candy) = 9220.205 KJ / 4.90 g

C(candy) =  1881.674 KJ / g

It is known that,

1 KJ /g = 239.006 cal/g

1881.674 × 239.006 = 449730.879 cal/g

8 0
3 years ago
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