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lianna [129]
3 years ago
13

There are 680 raisins in 8 bags. If each bag has the same number of raisins, how many raisins are in 12 bags?

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0
In 12 bags there would be 1,020 raisins.
Hoped this helped please mark as brainliest answer. :)
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A rectangular carpet has a perimeter of 194 inches. The length of the carpet is 67 inches more than the width. What are the dime
sammy [17]

Answer:

The dimensions of the carpet are 15 inches and 82 inches

Step-by-step explanation:

Assume that the width of the carpet is x inches

∵ The width of the carpet is x inches

∵ The length of the carpet is 67 inches more than the width

∴ The length of the carpet is (x + 67) inches

∵ The perimeter of the rectangle = 2(length + width)

∵ The perimeter of the carpet = 194 inches

→ Equate the two right sides of the perimeter

∴ 2(length + width) = 194

→ Divide both sides by 2

∴ length + width = 97

→ Substitute the value of the length and width in the equation above

∵ x + 67 + x = 97

→ Add the like terms in the left side

∴ (x + x) + 67 = 97

∴ 2x + 67 = 97

→ Subtract 67 from both sides

∵ 2x + 67 - 67 = 97 - 67

∴ 2x = 30

→ Divide both sides by 2

∴ x = 15

∵ x represents the width of the carpet

∴ The width of the carpet is 15 inches

∵ The length of the carpet = 15 + 67

∴ The length of the carpet is 82 inches

∴ The dimensions of the carpet are 15 inches and 82 inches

3 0
3 years ago
Is the relation below a function? If it is a function, state its domain.
nasty-shy [4]

Answer:

not a function. domain = -2, 3, 8 (you don't have to write them in any specific order and you also don't need to write -2 twice)

Step-by-step explanation:

to be a function, all of the x's must be different

4 0
3 years ago
Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Giv
Marianna [84]

Answer:

Correct options is (A).

Step-by-step explanation:

A (1 - <em>α</em>)% confidence interval can be constructed to determine whether there is any difference between the average GPA of seniors and the average GPA of sophomores.

The hypothesis can be defined as:

<em>H₀</em>: There is no difference between the average GPA of seniors and the average GPA of sophomores, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: There is a difference between the average GPA of seniors and the average GPA of sophomores, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

The (1 - <em>α</em>)% confidence interval for the difference between two means is:

CI=(\bar x_{1}-\bar x_{1})\pm z_{\alpha /2}\times SE

Decision rule:

If the confidence interval contains the mull value, i.e. 0, then the null hypothesis will be failed to be rejected and vice-versa.

The 95% confidence interval for the difference between the true average GPAs (seniors - sophomores) is (0.53, 1.61).

The 95% confidence interval dos not contains 0. Thus, the null hypothesis will be rejected.

Conclusion:

There is a significant difference between the average GPA of seniors and the average GPA of sophomores.

The 95% confidence interval for the difference between the true average GPAs (0.53, 1.61), implies that there is a 95% confidence that the average GPA of seniors is greater than the average GPA of sophomores.

Thus, the correct options is (A).

4 0
3 years ago
Choose the correct simplification of the expression (a2)3
Free_Kalibri [48]
The answer should be a^6
7 0
3 years ago
Read 2 more answers
yael used to have a square garage with 292ft^2 of floor space.she recently built an addition to it. The garage is still a​ squar
Arturiano [62]

Answer: 19

If the floor space of the garage is increased by 50%, that means its area is increased by that amount

So we have 228 + .50(228) = 228 + 114 = 342 ft²

Since the original garage is square-shaped with an area of 228 ft², then we can find the length of each side. If we let x = the side length, then we have:

x² = 228

x = 15.1 ft

Assuming that the garage will remain square-shaped with sides of uniform dimensions, then we can label each side of the expanded garage as 15 + y. We need to solve for y. Again, we use the area formula. Remember that the expanded garage will have an area of 342 ft², we now have:

(y + 15)² = 342

y² + 30y + 225 = 342

y² + 30y - 117 = 0

This can be solved using the Quadratic Formula. Remember that dimensions must always be positive. Once you determine y, then you will know what the length will be of the expanded garage

8 0
3 years ago
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