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2 years ago

What holds the atoms together in a covalent bond

2 answers:

5 0

In covalent bonding, both atoms are trying to attract electrons--the same electrons. Thus, the electrons are shared tightly between the atoms. The force of attraction that each atom exerts on the shared electrons is what holds the two atoms together.

Juli2301 [7.4K]2 years ago

3 0

Answer:

the attraction between shared electrons and protons in each nucleus

Explanation:

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Lúc 7g bạn an đi từ nhà đến trường với tóc độ trung bình là 20km/h . Bạn đến trường lúc 7g20. Tính khoảng cách từ nhà tới trường

Len [333]

Answer:

Distance = 6.667 kilometres

Explanation:

Given the following data;

Speed = 20 km/h

Departure time = 7:00

Arrival time = 7:20

Time taken = 20 minutes

To calculate the distance travelled from home to school;

First of all, we would have to convert the value of time in minutes to hours.

Conversion:

60 minutes = 1 hour

20 minutes = X hours

Cross-multiplying, we have;

X = 20/60 = 1/3 hours

Mathematically, the distance travelled by an object is calculated by using the formula;

Distance = speed * time

Distance = 20 * 1/3

Distance = 20/3 =

Distance = 6.667 kilometres

7 0

2 years ago

_____ are formed where bumps from two surfaces come into contact ?

Murrr4er [49]

Answer:

the answer would be microwelds.

3 0

2 years ago

Scientists study how the continents move. Why might scientists use a model

tigry1 [53]

Answer:

B. It is too slow to observe directly

Explanation:

They move too slow to be able to observe how they move.

I hope it helps! Have a great day!
bren~

3 0

2 years ago

Solve for the BMI weight 58kg Height 1.61

vaieri [72.5K]

Answer:

Explanation:

BMI= weight/(height × height) ; weight in kilogram and height in metter

= 58kg / (1.61m × 1.61m )

= (58/ 2.5921) kg/ $m^{2}$

= 22.375 kg/ $m^{2}$

≈ 22.4 kg/ $m^{2}$

7 0

2 years ago

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

$\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}$

$\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}$

$\frac{3-y}{y}=\sqrt{\frac{7}{2}}$

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0

3 years ago