A 580-turn solenoid is 18 cm long. The current in it is 36 A. A straight wire cuts through the center of the solenoid, along a 2
.0-cm diameter. This wire carries a 27-A current downward (and is connected by other wires that don't concern us). What is the magnitude of the force on this wire assuming the solenoid's field points due east?
2 answers:
Answer:
F = 0.078N
Explanation:
In order to calculate the magnitude of the force on the wire you first calculate the magnitude of the magnetic field generated by the solenoid, by using the following formula:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
N: turns of the solenoid = 580
i: current in the solenoid = 36A
L: length of the solenoid = 18cm = 0.18m
You replace the values of all parameters in the equation (1):
Next, you calculate the force exerted on the wire, by using the following formula:
(2)
i: current in the wire = 27A
L: length of the wire that perceives the magnetic field (the same as the radius of the solenoid) = 2.0 cm = 0.02m
θ: angle between wire and the direction of B
B: magneitc field in the solenoid = 0.145T
The direction of the wire are perpendicular to the direction of the magnetic field, hence, the angle is 90°.
You replace the values of the parameters in the equation (2):
The magnitude of the force on the wire is 0.078N
You might be interested in
Answer:
The speed does it head toward the goal = 41.87
Explanation:
Mass = 0.107 kg
Initial velocity ( u ) = 0
Force (F) = 28 N
Time = 0.16 sec
From newton's second law, Force = mass × acceleration
⇒ F = m × a
⇒ 28 = 0.107 × a
⇒ a = 261.7 --------- (1)
This is the value of acceleration.
Final speed of the mass is calculated by the equation V = U + at
⇒ U = 0 because mass in in rest position at start.
⇒ V = a t
Put the values of acceleration and time in above formula we get
⇒ V = 261.7 × 0.16
⇒ V = 41.87
Therefore the speed does it head toward the goal = 41.87