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Komok [63]
3 years ago
13

A swimmer swam 0.8 mi at 0.0321 mi per min in waters created by melted sea ice. What was his time?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0

Remark

He's very lucky to be alive.

Givens

distance = d = 0.8 miles

Rate = r   =       0.0321 mi per minute

Time = t = ??

<u>Formula</u>

d = r * t

<u>Solve</u>

0.8 = 0.0321 * t      Divide by 0.0321

0.8/0.0321 = t

t = 24.92 minutes  <<<< Answer

Amiraneli [1.4K]3 years ago
6 0

0.0321 miles per minute, simply means, in 1 minute, it does 0.0321 miles.


\bf \begin{array}{ccll}&#10;miles&minutes\\&#10;\cline{1-2}&#10;0.0321&1\\&#10;0.8&x&#10;\end{array}\implies \cfrac{0.0321}{0.8}=\cfrac{1}{x}\implies 0.0321x=0.8&#10;\\\\\\&#10;x=\cfrac{0.8}{0.0321}\implies x\approx 24.92211838

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lubasha [3.4K]

Answer:

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Step-by-step explanation:

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dT/dt = - K(T - Ts)

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Ts = Surrounding Temperature

First, we will use the data of cooling of body from 28°C to 27°C to find the cooling constant of the body:

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dt = ?

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