All categories

3 years ago

A swimmer swam 0.8 mi at 0.0321 mi per min in waters created by melted sea ice. What was his time?

Mathematics

2 answers:

CaHeK987 [17]3 years ago

8 0

Remark

He's very lucky to be alive.

Givens

distance = d = 0.8 miles

Rate = r = 0.0321 mi per minute

Time = t = ??

<u>Formula</u>

d = r * t

<u>Solve</u>

0.8 = 0.0321 * t Divide by 0.0321

0.8/0.0321 = t

t = 24.92 minutes <<<< Answer

Amiraneli [1.4K]3 years ago

6 0

0.0321 miles per minute, simply means, in 1 minute, it does 0.0321 miles.

$\bf \begin{array}{ccll}
miles&minutes\\
\cline{1-2}
0.0321&1\\
0.8&x
\end{array}\implies \cfrac{0.0321}{0.8}=\cfrac{1}{x}\implies 0.0321x=0.8
\\\\\\
x=\cfrac{0.8}{0.0321}\implies x\approx 24.92211838$

You might be interested in

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

A store purchases a bicycle from the manufacturer for $150. The store then sells the bicycle for $215. By what percentage did th

Nookie1986 [14]

Answer:

it marked the bike up by 69 percent

Step-by-step explanation:

7 0

3 years ago

Help please

andre [41]

I am pretty sure that it is B

6 0

3 years ago

What is the length of the diagonal of the rectangular solid shown? please help!!!!

Olin [163]

Answer:

D. diagonal = 20.10 cm

Step-by-step explanation:

Find the bottom diagonal using the length and width.

diagonal² = 8² + 12²

diagonal = √64+144

diagonal = √208

diagonal = 4√13

---------------------------------------------------------------------------------------------------------

Find diagonal of the rectangular solid:

diagonal² = (4√13)² + 14²

diagonal² = 208 + 196

diagonal = √404

diagonal = 20.10 cm

7 0

2 years ago

You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num

AnnyKZ [126]

Answer:

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2 Combine like terms

2.80 = 0.35d + 2 Subtract 2 from both sides

0.80 = 0.35d Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

5 0

2 years ago