Ask question

Ask question

All categories

Delicious77 [7]

3 years ago

10

Make A the subject of the formula

7D%20" id="TexFormula1" title="r = \sqrt{ \frac{2a}{3} } " alt="r = \sqrt{ \frac{2a}{3} } " align="absmiddle" class="latex-formula">

1 answer:

alexandr402 [8]3 years ago

7 0

Answer:

a = (3r^2)/2

Step-by-step explanation:

Start by squaring both sides. Then we have

r^2 = 2a/3

r^2 * 3 = 2a/ 3 * 3 multiply both sides by 3.

3r^2 = 2a

2a/2 = 3r^2/2 divide both sides by 2.

a =(3r^2)/2

Hope it helps you and if it does, please mark me brainliest...

You might be interested in

while swimming in the pool, you attempt to swim the whole length of the pool without getting a breath. you are able to do it 3 o

Luba_88 [7]

Answer:

30 out of 50 times.

Step-by-step explanation:

1 attempt represents 3 out of 5 times.

10 attempts equals 1 attempt x 10.

Multiply numbers 3 and 5 by 10.

3 x 10 = 30

5 x 10 = 50.

Therefore, your solution is 30 / 50 times.

6 0

3 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

<em><u>Solution:</u></em>

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

<em><u>Use the following log rules</u></em>

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

Next

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

Next

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

Next

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

2 years ago

→ PLEASE HELP ME! [99 POINTS] ←

zaharov [31]

B.

The cost for x children and y adults to go to the movies if adult tickets are $11 and child tickets are $6.

Example 3 children and 2 adults ( 6(3) + 11(2) )

5 0

3 years ago

Read 2 more answers

(-3x^2+4x-2)/(-3x+19)

prohojiy [21]

\left[x _{1}\right] = \left[ \frac{2}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{2}\right][x1]=[32+(3−1i)√2] totally answer

7 0

2 years ago

Read 2 more answers

What is the solution to this equation 1/2n^2+18=0

ololo11 [35]

Answer:

n = ±6 .

Step-by-step explanation:

A quadratic equation is given to us and we need to find out the solution of the given equation . The given equation is ,

$\rm\implies -\dfrac{1}{2}n^2+18=0$

Subtracting 18 both sides ,

$\rm\implies -\dfrac{1}{2}n^2 = -18$

Multiplying both sides by -2 ,

$\rm\implies -2\times\dfrac{1}{2}n^2 = -2\times -18$

On simplyfing , we get ,

$\rm\implies n^2= 36$

Putting squareroot both sides ,

$\rm\implies n= \sqrt{36}$

This equals to ,

$\rm\implies \boxed{\quad\blue{\rm n =\pm 6 }}$

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>n </u><u>is </u><u>±</u><u>6</u><u> </u><u>.</u>

6 0

3 years ago