If

then the derivative is

Critical points occur where
. This happens for



In the first case, we find

In the second,

So all the critical points occur at multiples of
, or
. (This includes all the even multiples of
.)
Answer:
See below
Step-by-step explanation:
Part A
<em><u>Formula</u></em>
M = 2/3 * log(E/Eo)
<em><u>Givens</u></em>
M = ??
E = 2 * 10^15 joules
Eo = 10^4.4
<em><u>Solution</u></em>
M = (2/3) * log(2 * 10^15 / 10^4.4)
M = (2/3 ) log (7.96 * 10 ^ 11)
M = (2/3) * 11.901
M = 7.934
Part B
What the question is saying is that E/Eo = 10000
You don't have to figure out exact values.
M = 2/3 * log(10000)
M = 2/3 * 4
M = 8/3 or 2 2/3 or 2.66667
If you have choices, please list them.
Whete are the given points, is thee a picture
I must assume that you meant the following:
10(Q-3R)
P = ----------------
R
Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.
Rearranging these terms so that powers of R are in descending order:
30R^2 - 10RQ + PR = 0
Factoring out R, we get
R(30R - 10Q + P) = 0. This has two solutions:
R = 0, and 10Q - P
30R = 10Q - P, so that R = --------------
30