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Nadusha1986 [10]
3 years ago
7

Are the corresponding sides of similar hexagons are always congruent

Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Two polygons are similar if their corresponding angles are congruent and their sides are in proportion.

The sides could be in a ration of 1:1 in which case the two hexagons have corresponding sides that are congruent, but they do not have to be. It could be the case that the sides of one are twice the length of the other so the ratio is 2:1. In this case the hexagons have the same shape but not the same size.

So the answer is this, the corresponding sides of similar hexagons may be congruent but do not have to be.
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer
lyudmila [28]

If

f(\theta)=10\cos\theta+5\sin^2\theta

then the derivative is

f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta

Critical points occur where f'(\theta)=0. This happens for

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-10\sin\theta(1-\cos\theta)=0

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In the first case, we find

-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi

In the second,

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3 years ago
Janine inflated a ball to a radius of 18cm and another ball to a radius of 12cm. How much greater was the volume of the air in t
bagirrra123 [75]

Answer:

17,182.08 cm³

Step-by-step explanation:


6 0
3 years ago
On the Richter scale, the magnitude, M, of an earthquake is given by M= 2/3logE/Eo, where E is the energy released by the earthq
Ivahew [28]

Answer:

See below

Step-by-step explanation:

Part A

<em><u>Formula</u></em>

M = 2/3 * log(E/Eo)

<em><u>Givens</u></em>

M = ??

E = 2 * 10^15 joules

Eo = 10^4.4

<em><u>Solution</u></em>

M = (2/3) * log(2 * 10^15 / 10^4.4)

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M = (2/3) * 11.901

M = 7.934

Part B

What the question is saying is that E/Eo = 10000

You don't have to figure out exact values.

M = 2/3 * log(10000)

M = 2/3 * 4

M = 8/3 or 2 2/3 or 2.66667

If you have choices, please list them.

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3 years ago
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iris [78.8K]
Whete are the given points, is thee a picture

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Make R the subject<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7BP%3D10%28Q-3R%29%7D%7BR%7D" id="TexFormula1" title=" \frac
Naddik [55]

I must assume that you meant the following:

10(Q-3R)

P = ----------------

R

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30R^2 - 10RQ + PR = 0

Factoring out R, we get

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R = 0, and 10Q - P

30R = 10Q - P, so that R = --------------

30

8 0
3 years ago
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