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N76 [4]
2 years ago
6

Find the equation of a line parallel to line y=6 that passes through the point (-2,-1)

Mathematics
1 answer:
ohaa [14]2 years ago
4 0

Answer:

y=-1

Step-by-step explanation:

yeah-ya...... right?

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16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem? ​
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Answer:

x = 2

Step-by-step explanation:

16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} --> (16 = 2^{4} and 8 = 2^{3} )

2^{12x} = 2^{3x+18}

Since the base number is 2, the exponents must equal each other.

So:

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Consider the function represented by 9x + 3y= 12 with x as the independent variable. How can this function be written
Elena-2011 [213]

Answer: f(x) = -3x + 4

Step-by-step explanation:

The function is represented by

9x + 3y= 12

This is a linear equation with x as the independent variable. This means that if x is the independent variable, the y is the dependent variable. The values of y depends on the values of x. In order to represent the function, 9x + 3y= 12, we would rearrange the function such that y stands alone on the left hand side of the equation. This becomes

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Dividing the lefthand side and right hand side of the equation by 3, it becomes

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