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kobusy [5.1K]
3 years ago
14

If 320 J of work is done on a spring with a spring constant of 730 N/m, how far will it stretch?

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

0.94 m

Explanation:

EE = ½ kx²

320 J = ½ (730 N/m) x²

x = 0.94 m

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