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kobusy [5.1K]
3 years ago
14

If 320 J of work is done on a spring with a spring constant of 730 N/m, how far will it stretch?

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

0.94 m

Explanation:

EE = ½ kx²

320 J = ½ (730 N/m) x²

x = 0.94 m

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Answer:

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Polarity makes water a good solvent, gives it the ability to stick to itself (cohesion), stick to other substances (adhesion), and have surface tension (due to hydrogen bonding).

When the two hydrogen atoms bond with the oxygen, they attach to the top of the molecule. This molecular structure gives the water molecule polarity, or a lopsided electrical charge that attracts other atoms. The end of the molecule with the two hydrogen atoms is positively charged.

Explanation:

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Jazz is a 172 lb athlete who exercised at 7.6 METs. At this workload, what is his energy expenditure in kcals/min.? Round to the
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Answer:

Energy expenditure in K cals/min = 10 K cals /min (approximately)

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As we know

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putting the values in formula,

Energy expenditure in K cals/min=  7.6 x 3.5 x 78.02 / 200

                                                       =10.38 K cals /min

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Therefore, Energy expenditure in K cals/min by Jazz will be approximately 10 K cals /min

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A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done
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  • Force=150N
  • Angle=60°
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\boxed{\sf W=Fscos\Theta}

\\ \sf\longmapsto W=150(50)cos 60

\\ \sf\longmapsto W=7500\times \dfrac{1}{2}

\\ \sf\longmapsto W=3750J

6 0
2 years ago
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