Answer:
Explanation:
The capacitance of the parallel-plate capacitor is given by:
where
is the vacuum permittivity
is the area of the plates
is the separation between the plates
Substituting,
The energy stored in the capacitor is given by
Since we know the energy
we can re-arrange the formula to find the charge, Q:
1 g = 1 ÷ 1000 kg
= 0.001 kg
1 cm³ = 1 ÷ 100 ÷ 100 ÷ 100 m³
= 0.000001 m³
1 g/cm³ = 1 g / 1 cm³
= 0.001 kg / 0.000001 m³
= 1000 kg/m³
The density is 1000 kg/m³.
Explanation:
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