A 1,160 kg satellite orbits earth with a tangential speed of 7,446 m/s. if the satellite experiences a centripetal force of 8,95
1 answer:
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Answer:
The maximum height covered is 3.25 m.
The horizontal distance covered is 9.81 m.
The total time in the air is 1.63 seconds.
Explanation:
The launch speed, .
Angle of launch with the horizontal,
So, the vertical component of the initial velocity,
.
The horizontal component of the initial velocity,
Let, t be the time of flight, to the horizontal distance covered
.
Not, applying the equation of motion in the vertical direction.
Where s is the displacement in time t, u is the initial velocity and a is the acceleration.
In this case, (from equation (i), s=0 (as the final height is same as the launch height) and
(negative sign is due to the downward direction).
seconds.
So, the total time in the air is 1.63 seconds.
From equation (i),
Total horizontal distance covered is
.
Now, for the maximum height, H, applying the equation of motion as
Here, v is the final velocity and v=0 (at the maximum height), and h=H.
So,
.
Hence, the maximum height covered is 3.25 m.
Answer:
v= 4.0 m/s
Explanation:
- When standing on the bathroom scale within the moving elevator, there are two forces acting on Henry's mass: Normal force and gravity.
- Gravity is always downward, and normal force is perpendicular to the surface on which the mass is located (the bathroom scale), in upward direction.
- Normal force, can adopt any value needed to match the acceleration of the mass, according to Newton's 2nd Law.
- Gravity (which we call weight near the Earth's surface) can be calculated as follows:
- According to Newton's 2nd Law, it must be met the following condition:
- As the gravity is larger than normal force, this means that the acceleration is downward, so, we choose this direction as the positive.
- Solving for a, we get:
- We can find the speed after the first 3.8 s (assuming a is constant), applying the definition of acceleration as the rate of change of velocity:
- Now, if during the next 3.8 s, normal force is 930 N (same as the weight), this means that both forces are equal each other, so net force is 0.
- According to Newton's 2nd Law, if net force is 0, the object is either or at rest, or moving at a constant speed.
- As the elevator was moving, the only choice is that it is moving at a constant speed, the same that it had when the scale was read for the first time, i.e., 4 m/s downward.