Hey there!:
Balanced Equation , for the reaction:
3 H₂SO₄(aq) + 2 Fe(s) → Fe₂(SO₄)₃(aq) + 3 H₂(g)
2 moles Fe ---------------------------------- 3 moles H₂
0.250 moles Fe ---------------------------- ( moles H₂ ) ??
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moles H₂ = 0.250 × 3 / 2
moles H₂ = 0.75 / 2
moles = 0.375 moles of H₂
Hope this helps!
Answer:
4.
Explanation:
It's neither qualitative and quantitative. Qualitative is speculation on quality, and quantitative is speculation on quantity, or the amount of something.
Answer:
0.028kg
Explanation:
We were given 2.6 × 1023 molecules of SO 2 That means that
N = 2.6 × 1023 molecules
Use
n (number of moles) = N
NA (Avogadro's constant)
to get
n =2.6×1023 molecules
6.02 ×1023 molecules/mol = 0.432 moles
Now use
m = n × M (molar mass)
to get
m = 0.432 mol × 64.066 g/mol = 27.677 g
So
m (in kilograms) = 27.677 g
103 g/kg = 0.028 kg
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:
Best regards!
