Answer is: the number of ions produced in the dissociation of aluminium fluoride is 4.
<span>
Chemical dissociation of aluminium fluoride in
water:
AlF</span>₃(aq) →
Al³⁺(aq) + 3F⁻(aq).<span>
There are four ions, one aluminium cation and
three fluoride anions.
Aluminium has oxidation +3, because it lost
three electrons, to have electron configuration as noble gas neon and fluorine has oxidation -1, because it gain one electron to </span>have electron configuration as noble gas neon.
In this reaction
ester is reduced to
aldehyde. Such reduction can not be achieved by reacting reducing agents like
LiAlH₄ because it will further reduce aldehydes to alcohols. So, in order to stop reduction at alddehyde, ester is reacted with bulky reducing agent, <span>
Diisobutylaluminium hydride (DIBAL) which works with same mechanism as that LiAlH</span>₄ do. It also add hydride to carbonyl group. The reaction is shown below,
Copper.
Easy to look up, why use brainly? ;P
<h3>
Answer:</h3>
18.02 g/mol
<h3>
General Formulas and Concepts:
</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>Explanation:
</h3>
<u>Step 1: Define</u>
Water H₂O
<u>Step 2: Find Formulas Mass</u>
<em>Formula mass is molar mass.</em>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol