Divide the 181g by the mol mass of the compound. Just add up the masses of the various elements.
Answer:
The molar mass of N5O9
is 214.0245g/mol
Explanation:
To solve this problem, we need to know each number of mole of each element present in the compound
N has 5 moles
O has 9 moles
Then, we multiple each number of mole by its number of mass of each element present
N - 14.0067
O - 15.999
Multiplying by mole
N - 5 * 14.0067 = 70.0335
O - 9 * 15.999 = 143.991
Therefore,
Molar mass of N5O9 = 70.0335 + 143.991
= 214.0245g/mol
I think it’s B and why is everyone putting a bunch of links?
Answer:
(1) -12 Kcal/mol
Explanation:
Our answer options for this question are:
(1) -12 Kcal/mol
(2) -13 Kcal/mol
(3) -15 Kcal/mol
(4) -16 Kcal/mol
With this in mind, we can start with the chemical reaction (Figure 1). In this reaction, <u>two bonds are broken</u>, a C-H and a Br-Br. Additionally, a C-Br and a H-Br are <u>formed</u>.
If we want to calculate the enthalpy value, we can use the equation:
<u>ΔH=ΔHbonds broken-ΔHbonds formed</u>
If we use the energy values reported, its possible to calculate the energy for each set of bonds:
<u>ΔHbonds broken</u>
<u />
C-H = 94.5 Kcal/mol
Br-Br = 51.5 Kcal/mol
Therefore:
105 Kcal/mol + 53.5 Kcal/mol = 146 Kcal/mol
<u>ΔHbonds formed</u>
C-Br = 70.5 Kcal/mol
H-Br = 87.5 Kcal/mol
Therefore:
70.5 Kcal/mol + 87.5 Kcal/mol = 158 Kcal/mol
<u>ΔH of reaction</u>
<u />
ΔH=ΔHbonds broken-ΔHbonds formed=(146-158) Kcal/mol = -12 Kcal/mol
I hope it helps!
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If you made the sugar and corn syrup solutions you heated, the sugar made the solutions' boiling points higher than that of pure liquid water.