Using the balanced equation N2+O2=2NO, how many grams of NO can be produced when 25.0 grams of N react?

Chemistry

1 answer:

Oxana [17]3 years ago

8 0

Answer:

$53.55gNO$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:

$=25.0gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNO}{1molN_2}*\frac{30.01 gNO}{1molNO}\\\\=53.55gNO$

Best regards!

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How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)?

soldier1979 [14.2K]

Answer:

The no. of moles of CaCl₂ are needed = 3.1 mol.

Explanation:

From the balanced reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂,

It is clear that 2 mol of AgNO₃ react with 1 mol of CaCl₂ to produce 2 mol of AgCl and 1 mol of Ca(NO₃)₂.

Using cross multiplication:

2 mol of AgNO₃ need → 1 mol of CaCl₂ to react completely, from stichiometry.

6.2 mol of AgNO₃ need → ??? mol of CaCl₂ to react completely.

∴ The no. of moles of CaCl₂ are needed = (1 mol)(6.2 mol)/(2 mol) = 3.1 mol.

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4 years ago

A metal object has a mass of 8.37g. When it was in a graduated cylinder containing 20.0 ml of water, the water level rose to 23.

Yuri [45]

Mass of metal is 8.37 g, volume of water in graduated cylinder is 20 mL. After adding the metal, water level increases to 23.1 mL. The volume of metal is equal to the increase in water level.

The increase in water level can be calculated by taking difference of final and initial level of water.

Thus,

$V_{metal}=V_{f}-V_{i}=(23.1-20)mL=3.1 mL$