The plug is 6 but u have to divert by the scale to form 5 .C
The answer would be B.
Since the light source comes from the bottom, you just need to find the sequence from the bottom going up.
It will start with the light source, then go through the slide, which will then go through the objective lens and lastly, the eyepiece lens. In summary, the sequence is:
B. Light --- slide ---- objective lens --- eyepiece lens
Answer:
11m/s
Explanation:
Given parameters:
Mass of the lead shot = 8kg
Energy of the shot = 484J
Unknown:
Velocity of the shot = ?
Solution:
To solve this problem, we apply the kinetic energy formula;
K.E = 
m v²
m is the mass
v is the unknown
Now, insert the parameters and solve;
484 = x 8 x v²
484 = 4v²
v² = 121
v = 11m/s
4 because its not yet moving. It has kinetic energy, it just hasn’t been used yet.
Distance = speed* time
10x10^-3 *u + 10x10^-3 * 2u = 125
0.01u + 0.02u = 125
0.03u = 125
u = 4166.66666.... s
acceleration = (final velocity - initial velocity)/time
(10x10-3 - 0)/4167 = 2.3998 * 10^-6 m s-2
