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Alexxx [7]
3 years ago
6

The diagram below shows a person swinging a hammer.

Physics
2 answers:
sleet_krkn [62]3 years ago
5 0
4 because its not yet moving. It has kinetic energy, it just hasn’t been used yet.
sweet [91]3 years ago
3 0

Answer:

D 4

Explanation:

If the swing is smoothly accelerating from momentary rest as a normal swing.

It would not have to be so.

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A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5
sweet [91]

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

 y = \dfrac{m\lambda\ D}{d}

for the first maxima, m = 1

 d = \dfrac{1\times \lambda\ D}{y}

 d = \dfrac{1\times  550 \times 10^{-9}\times 1.5}{0.016}

       d = 5.2 x 10⁻⁶ m

       d = 52 μm

hence, the width of her slits is equal to d = 52 μm

3 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
Sophie [7]

Answer:

a. Wavelength = λ = 20 cm

b. Next distance of maximum intensity will be 40 cm

Explanation:

a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.

Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.

This we get the equation:

(nλ + λ/2) - nλ = 30-20

λ/2 = 10

λ = 20 cm

b. at what distance, sound intensity will be maximum again.

For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.

= 30 + λ/2

= 30 + 20/2

=30+10

=40 cm

7 0
3 years ago
What do radio waves and microwaves have in common?
Lunna [17]

Both are at the side of the spectrum that has the lower frequency

8 0
3 years ago
Read 2 more answers
X-Rays at different wavelengths provide scientists studying objects in space with information about which of the following?
olganol [36]

Answer:

object composition

Explanation:

6 0
3 years ago
Read 2 more answers
Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a
Harrizon [31]

Answer:

The pressure exerted by camel feet is <u>2000 N/m²</u>.

Step-by-step explanation:

<h3><u>Solution</u> :</h3>

Here, we have given that ;

  • Force applied on camel feet = 4000 N
  • Total area of camel feet = 2 m²

We need to find the pressure exerted by camel feet.

As we know that :

{\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}

Substituting all the given values in the formula to find the pressure exerted by camel feet.

\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\  \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}}  \\  \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\  \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\  \\\star \:  \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}

Hence, the pressure exerted by camel feet is 2000 N/m².

\rule{300}{2.5}

3 0
2 years ago
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