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VLD [36.1K]
3 years ago
13

The color that is refracted the most has the___ wavelength

Physics
2 answers:
Gre4nikov [31]3 years ago
4 0

Answer:

The color that is refracted the most has the shortest wavelength

Explanation:

The warmer colors (yellow to red) have shorter wavelengths and the colder (green to violet) shorter wavelengths. Bearing in mind that light is radiant energy, the shorter the wavelength, the greater the frequency and the greater the amount of energy, allowing colors with shorter wavelengths to be more refracted.

The light can reflect in several ways but it follows a law: the angle of incidence is the same as the starting angle. If the light reflects on a perfectly smooth surface, such as in a mirror (which is glass with a silver film), the light will be reflected exactly as it did. That is why we see an image totally faithful in form and color when we see ourselves in the mirror. But if the object is not smooth, it will reflect part of the incident light and absorb the rest. The illumination of this object will reveal only its own color, shape, texture and not the image of a reflection. Black objects absorb light completely and white objects reflect it completely. The colorful visual sensation of objects, in fact, is the detection and perception of the wavelength that they are reflecting.

irinina [24]3 years ago
3 0
The color that is refracted the most has the SHORTER wavelength. The shorter the wavelength,the more it gets refracted.
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Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
ki77a [65]

Answer:

The lowest possible frequency of sound for which this is possible is 1307.69 Hz

Explanation:

From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.

First, we will determine his distance from the second speaker using the Pythagorean theorem

l₂ = √(2.00²+5.00²)

l₂ = √4+25

l₂ = √29

l₂ = 5.39 m

Hence, the path difference is

ΔL = l₂ - l₁

ΔL = 5.39 m - 5.00 m

ΔL = 0.39 m

From the formula for destructive interference

ΔL = (n+1/2)λ

where n is any integer and λ is the wavelength

n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which corresponds to the smallest value of n.

Then,

0.39 = (1+ 1/2)λ

0.39 = (3/2)λ

0.39 = 1.5λ

∴ λ = 0.39/1.5

λ = 0.26 m

From

v = fλ

f = v/λ

f = 340 / 0.26

f = 1307.69 Hz

Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.

5 0
3 years ago
Which best describes a difference between laser light and regular light?
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4 0
3 years ago
Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t
zlopas [31]

Answer:

y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

Explanation:

As we know that the wave equation is given as

y = A sin(\omega t - k x + \phi_0)

now we have

A = 0.19 m

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so we have

k = \frac{2\pi}{\lambda}

k = \frac{2\pi}{2.6}

k = 2.42  per m

also we have

T = 1.2 s

so we have

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{1.2}

\omega = 5.23 rad/s

now we know that at t = 0 and x = 0 wave is at y = 0.19 m

so we have

\phi_0 = \frac{\pi}{2}

so we have

y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})

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