Question

Which graph represents y = RootIndex 3 StartRoot x EndRoot + 2?

Answer 1

Answer:

see attachment

Step-by-step explanation:

We want to choose the graph that represents:

$y = \sqrt[3]{x} + 2$

We know the parent function will be:

$y = \sqrt[3]{x}$

There has been a vertical shift upward by 2 units.

Therefore the graph of

$y = \sqrt[3]{x} + 2$

is obtained by shifting the parent function up 2 units.

Its y-intercept will move from 0 to 2.

The graph is shown in attachment.

Answer 2

Note: since, you forgot to add the graph, but I have solved your query in terms of explaining the graph of the described function which will anyways clear your concept.

Answer:

The graph of this function is also attached below.

Step-by-step explanation:

Given the function

$y=\sqrt[3]{x}+2$

$\mathrm{Domain\:of\:}\:\sqrt[3]{x}+2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}\sqrt[3]{x}+2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Axis\:interception\:points\:of}\:\sqrt[3]{x}+2:\quad \mathrm{X\:Intercepts}:\:\left(-8,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)$

$\mathrm{Asymptotes\:of}\:\sqrt[3]{x}+2:\quad \mathrm{None}$

$\mathrm{Extreme\:Points\:of}\:\sqrt[3]{x}+2:\quad \mathrm{Saddle}\left(0,\:2\right)$

The graph of this function is also attached below.