Answer: 
Explanation:
The balanced chemical reaction is,
The expression for Gibbs free energy change is,
![\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_%28reactant%29%5D)
![\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5B%28n_%7BCO_2%7D%5Ctimes%20%5CDelta%20G_%7BCO_2%7D%29%2B%28n_%7BCaO%7D%5Ctimes%20%5CDelta%20G_%7BCaO%7D%29%5D-%5B%28n_%7BCaCO_3%7D%5Ctimes%20%5CDelta%20G_%7BCaCO_3%7D%29%5D)
where,
n = number of moles
Now put all the given values in this expression, we get
![\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5B%281%5Ctimes%20-394.4%29%2B%281%5Ctimes%20-604.17%29%5D-%5B%281%5Ctimes%20-1128.76%29%5D)
Therefore, the gibbs free energy for this reaction is, +130.19 kJ
Answer: 7.71 + 4.31 + 1.7 + 4.00141=
17.72141
7.71 x 4.31 x 1.7 x 4.00141= 226.04433255
Explanation:
(i) 7.71 + 4.31 + 1.7 + 4.00141
= 7.71000+4.31000+1.70000+ 4.00141 [make like decimals]
= 17.72141 [By adding the corresponding places ]
(ii) 7.71 x 4.31 x 1.7 x 4.00141 =( 7.71 x 4.31) x 1.7 x 4.00141
= 33.2301 x 1.7 x 4.00141
= (33.2301 x 1.7) x 4.00141
= 56.49117 x 4.00141
= ( 56.49117 x 4.00141 )
= 226.04433255
Hence, 7.71 + 4.31 + 1.7 + 4.00141=
17.72141
7.71 x 4.31 x 1.7 x 4.00141= 226.04433255
