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Gwar [14]
4 years ago
7

A 0.21 m3 drum contains 100L of a mixture ofseveral degreasing solvents in water.The concentraton oftrichloroethylen in the head

space( gas phase) above the water wasmeasured to be 0.00301 atm.The Henry's constant fortrichloroethylene is 0.00985atm.m3.mol-1 at25o.What is the concentration of tricholoroethylene inthe water in units of molarity? ( assume that the temperature ofthe solution is 25o)
Chemistry
1 answer:
LiRa [457]4 years ago
5 0

Answer:

The concentration is 6.42×10^-4 M

Explanation:

Number of moles trichloroethylene = pressure × volume/Henry's constant = 0.00301×0.21/0.00985 = 0.0642 mol

Volume of mixture = 100 L

Concentration of trichloroethylene = number of moles of trichloroethylene/volume of solution = 0.0642/100 = 6.42×10^-4 M

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posledela

Answer:

p=\frac{nRT}{V}

Explanation:

The ideal gas law equation is an equation that relates some of the quantities that describe a gas: pressure, volume and temperature.

The equation is:

pV=nRT

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V is the volume of the gas

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R is the gas constant

T is the absolute temperature of the gas (must be expressed in Kelvin)

Here we want to solve the equation isolating p, the pressure of the gas.

We can do that simply by dividing both terms by the volume, V. We find:

p=\frac{nRT}{V}

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3 years ago
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alekssr [168]

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I grabbed these from my science notes, hope this helps.
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3 years ago
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kipiarov [429]

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3 years ago
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ahrayia [7]

Answer:

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So,

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