Of the five chosen for the committee the order in which they are chosen does not matter. A combination is defined as how many possible ways a group can be chosen. In this case students a,b,c,d,e is the same possibility as students e,d,c,b,a.
Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with 
rows and 
columns is 
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is ![\left[\begin{array}{ccc}0&-4&6\\2&-10&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-4%266%5C%5C2%26-10%264%5Cend%7Barray%7D%5Cright%5D)
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is 
as it has 3 rows and 2 columns.
The order of matrix 3B is 
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
Answer: 10 * 10*10
Step-by-step explanation:
<span>the difference between the largest and smallest data values in a data set.</span>
Answer:
s = 2t₁ + t₂
3 possible combinations:
t₁ = 0 min , t₂ = 8 min
t₁ = 1 min , t₂ = 6 min
t₁ = 2 min , t₂ = 4 min
Step-by-step explanation:
The distance covered by a body in uniform motion is given by the following equation:
s = vt
where,
s = distance
v = speed
t = time
For running:
s = s₁
t = t₁
v = 2 miles/min
Therefore,
s₁ = 2t₁
For walking:
s = s₂
t = t₂
v = 1 miles/min
Therefore,
s₂ = t₂
And the total distance will be:
s = s₁ + s₂
<u>s = 2t₁ + t₂</u>
where,
s = total distance covered in miles
t₁ = running time in min
t₂ = walking time in min
Now, the total distance is given as 8 miles:
8 = 2t₁ + t₂
So, the 3 possible combinations of time to satisfy this equation can be:
<u>t₁ = 0 min , t₂ = 8 min</u>
<u>t₁ = 1 min , t₂ = 6 min</u>
<u>t₁ = 2 min , t₂ = 4 min</u>
