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Eva8 [605]
3 years ago
15

I will mark as brillianest...plzz solve the question.Factorize: 1) 6x²+x-2​

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

( 2 − 1 ) ( 3 + 2 )

Step-by-step explanation:

6 ² + − 2

6x² + 4 - 3 -2

2 ( 3 + 2 )− 1 ( 3 +2 )

( 2 − 1 ) ( 3 + 2 )

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Solve for x<br><br> x+0.15x=3.45
otez555 [7]
Answer: x should equal 3
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
HELP please.
Delvig [45]

Answer:

Q1: \frac{3}{4}

Q2: \frac{83}{100}

Step-by-step explanation:

Q1: 12 : 16 = 3 : 4 = \frac{3}{4}

Q2: 8.3 : 10 = \frac{83}{100}

3 0
3 years ago
The area of trapezoid TRAP is 100 m squared
Anastasy [175]
Answer:  30 m ; (or, write as: "30 meters") .
______________________________________________
Explanation:
____________________

Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
______________________________________________
or, write as:  A = ( b₁ + b₂) h  / 2 ;
___________________________________
in which:  A = area;
              b₁ = length of "base 1" (choose either one of the 2 (two bases);
              b₂ = length of "base 2" (use the base that is remaining);
              h = height of trapezoid;
____________________________________________
From the information given: 
___________________________
A = 100 m² ; 
h = 5 m
b₁ = 10 m
b₂ =  x 
___________________________
Find "x", which is:  "b₂" ;
__________________________
      A = ( b₁ + b₂) h  / 2  ;
_____________________________
Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
_________________________________________________________
  100 m² = [(10m + x) (5m)] / 2  ; Solve for "x" ;
_________________________________________________________
          (10m + x) (5m) = (2)* (100m²) ;
_________________________________________________________
             (5m) (10m + x) = 200 m² ;
___________________________________________
Note:  The distributive property of multiplication:
____________________________________________
    a(b+c) = ab + ac ;
 
    a(b−c) = ab <span>− ac ;
</span>____________________________________________

  We have:  (5m) (10m + x) = 200 m²  ;
____________________________________________
So:    (5m) (10m + x) =  (5m*10m) + (5m * x) ;
                           
                               =  50m² + (5m)x  ;
_______________________________________________
     →  50m² + (5m)x = 200m²  ; 
_______________________________________________
Divide the ENTIRE equation by "5m" ;
_______________________________________________
     → { 50m² + (5m)x } / 5m = (200m² / 5m) ;
_______________________________________________
     →  10m + x   = 40m ; 
________________________________________________
Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
_______________________________________
     →  10m + x  − 10m  =  40m − 10m ;

to get:

                →    x  =  30 m  ; which is our answer.
___________________________________________________
Answer:  30 m ; (or, write as: "30 meters") .
_____________________________________________________
6 0
3 years ago
The diameter of a circle is 34 millimeters. What is the circle's area?<br> Use 3.14 for ​.
icang [17]

Answer:

907.46 mm2

Step-by-step explanation:

Area of circle = (¶d^2)/4

d = 34 mm

Therefore

Area A = (3.14 x 34^2)/4

= 907.46 mm2

6 0
3 years ago
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