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USPshnik [31]
3 years ago
12

What is the volume of the triangular prism below

Mathematics
1 answer:
cestrela7 [59]3 years ago
7 0
The volume is 4.5 ft^3.

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In the equation y = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B3%7D%20" id="TexFormula1" title=" \frac{x}{3} " alt="
Likurg_2 [28]
                              x
Just rewrite   <span>y = ---- as    y = (1/3)x.  The unit rate is 1/3.
                              3</span>
7 0
3 years ago
What grade is 92% out of 115
KatRina [158]
To calculate this, we need to do the following:

92 * 115 = 10580 (we first multiply the percentage with our number)
 
10580 / 100 = 105.8 (and divide what we get by 100 to get the final answer)

And this is also already the answer: 105.8
5 0
3 years ago
Justin is redoing his bathroom floor with tiles measuring 6in by 13 in. the floor has an area of 8,500 in². what is the least nu
enyata [817]
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7 0
3 years ago
Read 2 more answers
6x-2y=24<br> how do u solve for y
Tatiana [17]
It's <span>Diophantine equation. 
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2

So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
\frac{24}{2} =12
So, we can solve it.

Now is the formula:
{\displaystyle {\begin{cases}x=x_{0}+n{\frac {b}{\gcd(a,\;b)}}\\y=y_{0}-n{\frac {a}{\gcd(a,\;b)}}\end{cases}}\quad n\in \mathbb {Z} .}

Second, we need the first pair (x0,y0) 
 if
x=0
then
y=(-12)

Third, we gonna use that formula:
{\displaystyle {\begin{cases}x=-n}\\y=-3(4+n)}\end{case}\quad n\in \mathbb {Z} .}
Congratulations! We solve it.


8 0
3 years ago
Read 2 more answers
Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)
Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }    Simplify inside each bracket

CD = \sqrt{(-16)^{2}+(4)^{2} }    Square the numbers

CD = \sqrt{256+16 }     Add inside the root

CD = \sqrt{272}    Enter into calculator

CD = 16.5  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0
3 years ago
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