What is the volume of the triangular prism below

What is the initial value of the equation shown? y = −2x − 5

omeli [17]

The initial value is -5

8 0

3 years ago

Read 2 more answers

Please asnerw this pic attached below

mamaluj [8]

Answer:

x = 30

Step-by-step explanation:

Look at triangle LMN.

m<NLM + m<M + m<MNL = 180

90 + m<M + 45 = 180

m<M = 45

Theorem: The measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.

<ONM is an exterior angle of triangle KMN.

The remote interior angles are <K and <M.

m<K + m<M = m<ONM

2x + 45 = 105

2x = 60

x = 30

Answer: x = 30

8 0

3 years ago

How do I find the side length of a square with an area of approximately 84 square centimeters

prohojiy [21]

84 divided by 4 gives your answer

5 0

3 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0

3 years ago

PLZZ HELP ASAPP!!(Plz anwer em right!)

Shalnov [3]

Answer:

2. D.) $\displaystyle \frac{4}{3}$

1. $\displaystyle ?$

Step-by-step explanation:

2.) Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES], so −¾ becomes 4⁄3.

1.) No illustration provided

Perhaps there was a typographical error?!

Though, I am still joyous to assist you.

7 0

3 years ago