Question

I really need to understand this question! Please answer

Answer 1

Answer:

- 3

Step-by-step explanation:

Using the law of logarithms

$log_{b}$ x = n ⇔ x = $b^{n}$

let $log_{b}$( $\frac{1}{b^3}$) = n

$log_{b}$( $b^{-3}$) = n, then

$b^{-3}$ = $b^{n}$

Since bases are the same on both sides then equate the exponents

⇒ n = - 3 → (4)