Question

A polynomial has been factored, as shown below: f(x) = (x − 9)(x + 12)(x − 24) What are the zeros of the polynomial? (5 points) a −9, 9, −12, 12, −24, 24 b −9, 12, −24 c 9, −12, 24 d 9, 12, 24

Answer 1

Answer:

The answer is Option c

9, -12, 24

Step-by-step explanation:

We have the polynomial:

 $f(x) = (x - 9)(x + 12)(x - 24)$

To find the zeros we must equal $f(x) = 0$

So:

$(x - 9)(x + 12)(x - 24) = 0$

Then the previous expression is equal to zero in any of these 3 cases:

Case 1

$(x-9) = 0\\x = 9$

Case 2

$(x + 12) = 0\\x = -12$

Case 3

$(x-24) = 0\\x = 24$

Then $f(x) = 0$ if   $x = 9$  or  $x = -12$ or  $x = 24$

The answer is 9, -12, 24