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3 years ago

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An inequality represents an infinite amount of numbers larger than –5. Which inequality represents the situation? x less-than ne

gative 5 x greater-than negative 5 x greater-than negative 4 x less-than negative 4

2 answers:

balu736 [363]3 years ago

7 0

Answer:

x greater-than -5

Step-by-step explanation:

Firlakuza [10]3 years ago

5 0

Step-by-step explanation:

An inequality represents an infinite amount of numbers smaller than 8. Which inequality represents the situation?

A.x greater-than 8

B.x less-than 8

C.x greater-than 7

D.x less-than 7

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Which of the following sets contains multiples of six?

Brrunno [24]

D, because it is the only one that contains multiples. All others contain factors.

If you have any doubts plz let me know.

8 0

3 years ago

What is the answer to 5+5=

HACTEHA [7]

The answer to 5+5 is 10

3 0

3 years ago

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HELP PLEASE I HAVE BEEN STUCK FOR HOURS THIS IS DUE- I'll mark brainliest. In parallelogram WXYZ, diagonal WY is drawn, M and N

dybincka [34]

Answer:

Opposite sides of the parallelogram are equal. Here, 60°+60°+ Angle ZWX + Angle ZYX = 360°

or,2* Angle ZYX = 240° [ Angle ZWX = Angle ZYX]

So, Angle ZYX = 120°

Then, In ∆ENY;

102° + (120-84)° + Angle ENY = 180° [Sum of all angles of a triangle.]

or, 36° + Angle ENY = 78°

So, Angle ENY = 42°

5 0

3 years ago

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Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

3 years ago

Pleaseee I needed the answerrr now

Bad White [126]

Step-by-step explanation:

Solution,

principle=4500
Time=3 years
Rate of interest=5%
Simple Interest=?

Simple Interest=

$\frac{ptr}{100} \\ \frac{4500 \times 3 \times 5}{100} \\ 675$

Hence, the simple Interest is 675.

7 0

3 years ago

Read 2 more answers